Profit and Loss
- The difference between the selling prices of an article at a profit of 15% and at a profit of 10% is $ 10. The cost price of the article is
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Let the CP of the article be y.
According to question ,∴ 115y - 110y = 10 100 100 ⇒ 5y = 10 100
Correct Option: D
Let the CP of the article be y.
According to question ,∴ 115y - 110y = 10 100 100 ⇒ 5y = 10 100 ⇒ y = 10 × 100 = $ 200 5
- A shopkeeper sold one-third of his goods at a loss of 15%. To get a profit of 10% on the whole transaction, he should sell the remaining articles at a profit of
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Let C.P. of all goods be Rs. 300.
C.P. of one - third goods = Rs. 100
∴ S.P. of one - third goods at 15% loss = Rs. 85Required S.P. of all the goods = 300 × 110 = Rs. 330 100
∴ S.P. of goods of worth Rs. 200 = Rs. (330 – 85) = Rs. 245
Profit = 245 - 200 = $ 45∴ Required profit percent = 45 × 100 200
Correct Option: A
Let C.P. of all goods be Rs. 300.
C.P. of one - third goods = Rs. 100
∴ S.P. of one - third goods at 15% loss = Rs. 85Required S.P. of all the goods = 300 × 110 = Rs. 330 100
∴ S.P. of goods of worth Rs. 200 = Rs. (330 – 85) = Rs. 245
Profit = 245 - 200 = $ 45∴ Required profit percent = 45 × 100 200 Required profit percent = 45 = 22 1 % 2 2
- A man bought 500 metres of electronic wire at 50 paise per metre. He sold 50% of it at a profit of 5%. At what percent should he sell the remainder so as to gain 10% on the whole transaction?
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At the rate of 50 paise per metre,
According to question ,C.P. of 250 metre of wire = Rs. 
250 × 50 
= Rs. 125 100
C.P. of 500 metre of wire = Rs. 250
∴ For 10% overall profit,Total S.P. = Rs. 250 × 110 = Rs. 275 100 S.P. of 250 metre of wire = Rs. 125 × 105 = Rs. 131.25 100
∴ S.P. of remaining 250 metre wire = Rs. (275 – 131.25) = Rs. 143.75
Profit = 143.75 - 125 = Rs. 18.75Correct Option: C
At the rate of 50 paise per metre,
According to question ,C.P. of 250 metre of wire = Rs. 250 × 50 = Rs. 125 100
C.P. of 500 metre of wire = Rs. 250
∴ For 10% overall profit,Total S.P. = Rs. 250 × 110 = Rs. 275 100 S.P. of 250 metre of wire = Rs. 125 × 105 = Rs. 131.25 100
∴ S.P. of remaining 250 metre wire = Rs. (275 – 131.25) = Rs. 143.75
Profit = 143.75 - 125 = Rs. 18.75∴ Required profit percent = Profit × 100 C.P. of 250 metre of wire Required profit percent = 18.75 × 100 = 15% 125
- Mr. Kapur purchased two toy cycles for Rs 750 each. He sold these cycles, gaining 6% on one and losing 4% on the other. The gain or loss per cent in the whole transaction is
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Given that , CP of each toy cycles = Rs 750 each
Total profit in sales = Rs. 750 × 6 - 750 × 4 100 100
Total profit in sales = Rs. (45 – 30) = Rs. 15or,Profit (6 – 4)% of 750 = 750 × 2 = Rs. 15 100
Correct Option: B
Given that , CP of each toy cycles = Rs 750 each
Total profit in sales = Rs. 750 × 6 - 750 × 4 100 100
Total profit in sales = Rs. (45 – 30) = Rs. 15or,Profit (6 – 4)% of 750 = 750 × 2 = Rs. 15 100 ∴ Profit percent = 15 × 100 = 1% 1500
- A man buys a table and a chair for Rs. 500. He sells the table at a loss of 10% and the chair at a gain of 10%. He still gains Rs.10 on the whole. The cost price of chair in rupees is :
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Here , C.P. of a table and a chair = Rs. 500
Let the C.P. of chair be Rs. y.
∴ C.P. of table = Rs. (500 – y)
According to the question,110y + (500 - y) × 90 = 510 100 100 ⇒ 11y + 500 × 9 - 9y = 510 10 10 10 ⇒ 2y + 450 = 510 10 ⇒ y = 60 × 10 = Rs. 300 2
Second method to solve this question :10% of y – (500 – y) × 10 = 10 100
Correct Option: C
Here , C.P. of a table and a chair = Rs. 500
Let the C.P. of chair be Rs. y.
∴ C.P. of table = Rs. (500 – y)
According to the question,110y + (500 - y) × 90 = 510 100 100 ⇒ 11y + 500 × 9 - 9y = 510 10 10 10 ⇒ 2y + 450 = 510 10 ⇒ y = 60 × 10 = Rs. 300 2
Second method to solve this question :10% of y – (500 – y) × 10 = 10 100 ⇒ y - 50 + y = 10 10 10 ⇒ 2y = 50 + 10 = 60 10
⇒ 2y = 60 × 10⇒ y = 60 × 10 = Rs. 300 2
