Percentage
- 31% of employees pay tax in the year 2008. Non-tax paying employees are 20,700. The total number of employees are :
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Let the total number of employees be x.
∴ x × 69 = 20700 100 ⇒ x = 20700 × 100 = 30000 69 Correct Option: C
Let the total number of employees be x.
∴ x × 69 = 20700 100 ⇒ x = 20700 × 100 = 30000 69
- A fruit seller had some apples. He sells 40% apples and still has 420 apples. Originally, he had :
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Let the fruit seller had originally x apples.
According to the question;
x – 40% of x = 420⇒ x - 40 × x = 420 100 ⇒ x - 2x = 420 5 ⇒ 5x - 2x = 420 5 ⇒ 3x = 420 5 ∴ x = 420 × 5 = 700 3
Method–2 :
60% = 420 (Directly)∴ 100% = 420 × 100 = 700 60 Correct Option: D
Let the fruit seller had originally x apples.
According to the question;
x – 40% of x = 420⇒ x - 40 × x = 420 100 ⇒ x - 2x = 420 5 ⇒ 5x - 2x = 420 5 ⇒ 3x = 420 5 ∴ x = 420 × 5 = 700 3
Method–2 :
60% = 420 (Directly)∴ 100% = 420 × 100 = 700 60
- Two numbers are more than the third number by 20% and 50% respectively. First number is what per cent of the second number ?
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Let third number = 100
First number = 120
Second number = 150
Required percentage= 120 × 100 = 80% 150
Aliter : Using Rule 30,
Required percentage= 
100 + 20 
× 100% 100 + 50 = 120 × 100% 150 = 4 × 100% = 80% 5 Correct Option: C
Let third number = 100
First number = 120
Second number = 150
Required percentage= 120 × 100 = 80% 150
Aliter : Using Rule 30,
Required percentage= 100 + 20 × 100% 100 + 50 = 120 × 100% 150 = 4 × 100% = 80% 5
- A batsman scored 110 runs which included 3 boundaries and 8 sixes. What per cent of his total score, did he make by running between the wickets ?
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The batsman scored 3 × 4 + 8 × 6 = 60 runs by boundaries and sixes respectively. Then,
Runs scored by running
= 110 – 60 = 50
∴ Required percentage= 50 × 100 = 500 = 45 5 % 110 11 11
Correct Option: B
The batsman scored 3 × 4 + 8 × 6 = 60 runs by boundaries and sixes respectively. Then,
Runs scored by running
= 110 – 60 = 50
∴ Required percentage= 50 × 100 = 500 = 45 5 % 110 11 11
- The price of an article was increased by r%. Later the new price was decreased by r%. If the latest price was 1, then the original price was :
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Let the initial value be A.
When it is increased by r% it becomes :A + r% of A = A (r + 100) 100
Now, when it is decreased by r%, it becomesA (r + 100) – % of 100 A (r + 100) 100
= A(r + 100) 1 - r 100 100 = A(r + 100)(r - 100) 10000 ∴ A 10000 - r2 = 1 10000 ⇒ A = ₹ 10000 10000 - r2 Correct Option: D
Let the initial value be A.
When it is increased by r% it becomes :A + r% of A = A (r + 100) 100
Now, when it is decreased by r%, it becomesA (r + 100) – % of 100 A (r + 100) 100
= A(r + 100) 1 - r 100 100 = A(r + 100)(r - 100) 10000 ∴ A 10000 - r2 = 1 10000 ⇒ A = ₹ 10000 10000 - r2
