Percentage
- A number is divided into two parts in such a way that 80% of 1st part is 3 more than 60% of 2nd part and 80% of 2nd part is 6 more than 90% of the 1st part. Then the number is
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First part = ₹ x and second part = ₹ y.
According to question,x × 80 = y × 60 + 3 100 100 ⇒ 4x = 3y + 3 5 5
⇒ 4x – 3y = 15 ....................(i)
Again,4y = 9x + 6 5 10
⇒ 8y = 9x + 60
⇒ 8y – 9x = 60 ...............(ii)
By equation (i) × 8 + (ii) × 3,32x – 24y = 120
24y – 27x = 1805x = 300 ⇒ x = 60
From equation (i)
4 × 60– 3y = 15
⇒ 3y = 240 – 15 = 225⇒ y = 225 = 75 3
∴ x + y = 60 + 75 = 135Correct Option: C
First part = ₹ x and second part = ₹ y.
According to question,x × 80 = y × 60 + 3 100 100 ⇒ 4x = 3y + 3 5 5
⇒ 4x – 3y = 15 ....................(i)
Again,4y = 9x + 6 5 10
⇒ 8y = 9x + 60
⇒ 8y – 9x = 60 ...............(ii)
By equation (i) × 8 + (ii) × 3,32x – 24y = 120
24y – 27x = 1805x = 300 ⇒ x = 60
From equation (i)
4 × 60– 3y = 15
⇒ 3y = 240 – 15 = 225⇒ y = 225 = 75 3
∴ x + y = 60 + 75 = 135
- A man invested 27,000 in
12 1 % 2
stock at 108, then his yield percentage is
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Value of ₹ 100 stock = ₹ 108
∵ Income on investing ₹ 108 = ₹ 25 2
∴ Income on investment of ₹ 27000= ₹ 25 × 27000 = ₹ 3125 2 × 108
∴ Gain per cent= 3125 × 100 27000 625 = 11 31 % 54 54 Correct Option: B
Value of ₹ 100 stock = ₹ 108
∵ Income on investing ₹ 108 = ₹ 25 2
∴ Income on investment of ₹ 27000= ₹ 25 × 27000 = ₹ 3125 2 × 108
∴ Gain per cent= 3125 × 100 27000 625 = 11 31 % 54 54
- The percentage of metals in a mine of lead ore is 60%. Now the percentage of silver is
of metals and the rest is lead. If the mass of ore extracted from this mine is 8000 kg, the mass (in kg.) of lead is :1 % 2
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Required mass of lead
= 8000 × 60 × 1 - 3 100 400 = 8000 × 60 × 397 = 4764 kg. 54 54 Correct Option: C
Required mass of lead
= 8000 × 60 × 1 - 3 100 400 = 8000 × 60 × 397 = 4764 kg. 54 54
- The sum of two positive numbers is 20% of the sum of their
squares and 25% of the difference of their squares. If the numbers are x and y then,x + y is equal to x2
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According to the question,
x + y = (x2 + y2) × 1 5 Again, x + y = (x2 + y2) × 1 4 ∴ x2 + y2 = x2 - y2 5 4
⇒ 5x2 – 5y2 = 4x2 + 4y2
⇒ 5x2 – 4x2 = 5y2 + 4y2
⇒ x2 = 9y2
⇒ x = 3y∴ x + y = x2 + y2 x2 5x2 = 9y2 + y2 = 10y2 = 2 5 × 9y2 45y2 9 Correct Option: D
According to the question,
x + y = (x2 + y2) × 1 5 Again, x + y = (x2 + y2) × 1 4 ∴ x2 + y2 = x2 - y2 5 4
⇒ 5x2 – 5y2 = 4x2 + 4y2
⇒ 5x2 – 4x2 = 5y2 + 4y2
⇒ x2 = 9y2
⇒ x = 3y∴ x + y = x2 + y2 x2 5x2 = 9y2 + y2 = 10y2 = 2 5 × 9y2 45y2 9
- A man bought some eggs of which 10% are rotten. He gives 80% of the remainder to his neighbours. Now he is left out with 36 eggs. How many eggs he bought ?
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Let the total number of eggs bought be x.
10% of eggs are rotten.
∴ Remaining eggs= 90x = 9x 100 10
After giving 80% of eggs to the neighbour,Remaining eggs = 9x × 20 = 9x 10 × 100 50
According to the question9x = 36 ⇒ 9x = 36 × 50 50 ⇒ x = 36 × 5 = 200 9 Correct Option: C
Let the total number of eggs bought be x.
10% of eggs are rotten.
∴ Remaining eggs= 90x = 9x 100 10
After giving 80% of eggs to the neighbour,Remaining eggs = 9x × 20 = 9x 10 × 100 50
According to the question9x = 36 ⇒ 9x = 36 × 50 50 ⇒ x = 36 × 5 = 200 9