Percentage
- 0.01 is what percent of 0.1 ?
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Let p% × 0.1 = 0.01
⇒ = p × 0.1 = 0.01 100 ⇒ p = 0.01 × 100 = 10 0.1 Correct Option: A
Let p% × 0.1 = 0.01
⇒ = p × 0.1 = 0.01 100 ⇒ p = 0.01 × 100 = 10 0.1
Hence , required percent is 10.
- If 20% of (P + Q) = 50% of (P –Q), then find P : Q
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Given that , 20% of (P + Q) = 50% of (P –Q)
⇒ 20(P + Q) = 50 ́(P - Q) 100 100 ⇒ P + Q = 5 ́ P - Q 2 ⇒ 2P = 5 + 2 ́ [By componendo & dividendo] 2Q 5 - 2
Correct Option: B
Given that , 20% of (P + Q) = 50% of (P –Q)
⇒ 20(P + Q) = 50 ́(P - Q) 100 100 ⇒ P + Q = 5 ́ P - Q 2 ⇒ 2P = 5 + 2 ́ [By componendo & dividendo] 2Q 5 - 2 ⇒ P = 7 ́ or 7 : 3 Q 3
- In a school 40% of the students play football and 50% play cricket. If 18% of the students neither play football nor cricket, the percentage of the students playing both is :
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As per the given details in question ,
Since 18% of the students neither play football nor cricket. It means 82% of the students either play football or cricket or both.
Using set theory
∴ n(A ∪ B) = n(A) + n(B) – n(A ∩ B)
⇒ 82 = 40 + 50 – n(A ∩ B)Correct Option: D
As per the given details in question ,
Since 18% of the students neither play football nor cricket. It means 82% of the students either play football or cricket or both.
Using set theory
∴ n(A ∪ B) = n(A) + n(B) – n(A ∩ B)
⇒ 82 = 40 + 50 – n(A ∩ B)
⇒ n(A ∩ B) = 90 – 82 = 8
∴ 8% students play both games.
- If 20% of A = 50% of B, then what percent of A is B ?
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Here , 20% of A = 50% of B
⇒ 2A = 5B ⇒ A = 5B 2
Let B is p % of A.∴ 5B × p ́ = B 2 100
Correct Option: B
Here , 20% of A = 50% of B
⇒ 2A = 5B ⇒ A = 5B 2
Let B is p % of A.∴ 5B × p ́ = B 2 100 ⇒ p = 200 = 40% 5
- If 50 % of P = 25% of Q, then P = y% of Q. Find y.
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Given that , 50 % of P = 25% of Q
P × 50 = Q × 25 ́ 100 100
⇒ P × 50 = Q × 25⇒ P = Q × 25 ⇒ P = Q ́ 50 2
P = Q y %∴ Q × y = Q ́ 100 2
Correct Option: C
Given that , 50 % of P = 25% of Q
P × 50 = Q × 25 ́ 100 100
⇒ P × 50 = Q × 25⇒ P = Q × 25 ⇒ P = Q ́ 50 2
P = Q y %∴ Q × y = Q ́ 100 2 ⇒ y = 100 = 50 2
