Percentage
- In a class 60% of the student pass in Hindi and 45% pass in Sanskrit. If 25% of them pass in at least one subject, what percentage of the students fail in both the subjects ?
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25% of students pass in at least one subject i.e.; they pass in one or both subjects.
∴ % of students who don’t pass or fail in both subjects
= (100 – 25)% = 75%Correct Option: B
25% of students pass in at least one subject i.e.; they pass in one or both subjects.
∴ % of students who don’t pass or fail in both subjects
= (100 – 25)% = 75%
- A student scored 32% marks in science subjects out of 300. How much should he score in language papers out of 200 if he is to get overall 46% marks ?
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46% of 500
= 500 × 46 = 230 100 32% of 300 = 300 × 32 = 96 100
Required marks = 230 – 96 = 134
Let x% of 200 = 134⇒ 200 × x = 134 100
⇒ 2x = 134⇒ x = 134 = 67% 2 Correct Option: B
46% of 500
= 500 × 46 = 230 100 32% of 300 = 300 × 32 = 96 100
Required marks = 230 – 96 = 134
Let x% of 200 = 134⇒ 200 × x = 134 100
⇒ 2x = 134⇒ x = 134 = 67% 2
- In an examination, a student had to obtain 33% of the maximum marks to pass. He got 125 marks and failed by 40 marks. The maximum marks were
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Let the maximum marks be x.
∴ x × 33 = 125 + 40 = 165 100 ⇒ x = 165 × 100 = 500 33
Aliter : Using Rule 24,
a = 33%, b = 125, c = 40
Maximum marks= (b + c) × 100 a = (125 + 40) × 100 33 = 165 × 100 = 500 33 Correct Option: A
Let the maximum marks be x.
∴ x × 33 = 125 + 40 = 165 100 ⇒ x = 165 × 100 = 500 33
Aliter : Using Rule 24,
a = 33%, b = 125, c = 40
Maximum marks= (b + c) × 100 a = (125 + 40) × 100 33 = 165 × 100 = 500 33
- For an examination it is required to get 36 % of maximum marks to pass. A student got 113 marks and failed by 85 marks. The maximum marks for the examination are :
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Let maximum marks be x,
then,36 × x = 113 + 85 = 198 100 ⇒ x = 198 × 100 = 550 36
Aliter : Using Rule 24,
a = 36%, b = 113, c = 85
Maximum marks= (b + c) × 100 a = (113 + 85) × 100 36 = 198 × 100 = 550 36 Correct Option: B
Let maximum marks be x,
then,36 × x = 113 + 85 = 198 100 ⇒ x = 198 × 100 = 550 36
Aliter : Using Rule 24,
a = 36%, b = 113, c = 85
Maximum marks= (b + c) × 100 a = (113 + 85) × 100 36 = 198 × 100 = 550 36
- In an examination 34% failed in Mathematics and 42% failed in English. If 20% failed in both the subjects, the percentage of students who passed in both subjects was
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Let total number of students = 100
Number of failures in Maths = 34
Number of failures in English = 42
Number of failures in both subjects = 20
Number of failures in Maths or English or both
= 34 + 42 – 20 = 56
Number of students who passed in both subjects
= 100 – 56 = 44
The required percentage = 44%
Aliter : Using Rule 23,
a = 34%, b = 42%, c = 20%
Passed candidates in both the subjects
= 100 – (a + b – c)
= 100 – (34 + 42 – 20)
= 100 – 56 = 44%Correct Option: C
Let total number of students = 100
Number of failures in Maths = 34
Number of failures in English = 42
Number of failures in both subjects = 20
Number of failures in Maths or English or both
= 34 + 42 – 20 = 56
Number of students who passed in both subjects
= 100 – 56 = 44
The required percentage = 44%
Aliter : Using Rule 23,
a = 34%, b = 42%, c = 20%
Passed candidates in both the subjects
= 100 – (a + b – c)
= 100 – (34 + 42 – 20)
= 100 – 56 = 44%
