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  1. The price of an article was increased by r%. Later the new price was decreased by r%. If the latest price was 1, then the original price was :
    1. 1
    2. 1 - r2
      100
    3. 1 - r2
      100
    4. 10000
      10000 r2
Correct Option: D

Let the initial value be A.
When it is increased by r% it becomes :

A + r% of A =
A (r + 100)
100

Now, when it is decreased by r%, it becomes
A (r + 100)
– % of
100

A (r + 100)
100

=
A(r + 100)
1 -
r
100100

=
A(r + 100)(r - 100)
10000

∴ A
10000 - r2
= 1
10000

⇒ A = ₹
10000
10000 - r2



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