Percentage
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A student multiplied a number by 3 instead of 5 5 3
What is the percentage error in the calculation ?
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Let p be the multiplicand.
∴ Error = 5 p - 3 p 3 5 Error = 25p - 9p = 16p 15 15 ∴ Percentage error = 16p × 100 15 5 p 3
Correct Option: D
Let p be the multiplicand.
∴ Error = 5 p - 3 p 3 5 Error = 25p - 9p = 16p 15 15 ∴ Percentage error = 16p × 100 15 5 p 3 ∴ Percentage error = 16p × 3 × 100 = 64% 15 5p
- If p% of p is 36, then p is equal to :
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Here , p% of p = 36
⇒ p × p = 36 100
⇒ p2= 3600
⇒ p = 60Correct Option: C
Here , p% of p = 36
⇒ p × p = 36 100
⇒ p2= 3600
⇒ p = 60
- 2 is what percent of 50?
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Let 2 be p% of 50 .
⇒ p% of 50 = 2⇒ p × 50 = 2 ⇒ p = 2 100 2
Correct Option: C
Let 2 be p% of 50 .
⇒ p% of 50 = 2⇒ p × 50 = 2 ⇒ p = 2 100 2
∴ p = 4
Hence , required percent is 4% .
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2 is what percent of 1 ? 3 3
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Let p % of 1 = 2 3 3
Correct Option: D
Let p % of 1 = 2 3 3 ⇒ p% = 2 × 3 = 2 ⇒ p = 200% 3
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0.15% of 33 1 % of 10000 is : 3
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According to question ,
0.15% of 33 1 % of 10000 3
Correct Option: A
According to question ,
0.15% of 33 1 % of 10000 3 Required answer = 0.15 × 100 × 10000 = ₹ 5 100 300
