Tricky Approach
Taking approximate values, we have

Correct Option: C

Tricky Approach
Taking approximate values, we have

Let number (dividend) be P.
∴  P = 296 × Q + 75 , where Q is the quotient and can have the values 1, 2, 3 etc.
P = 37 × 8 × Q + 37 × 2 + 1

Remark : From above it is clear that when the second divisor is a factor of the first divisor, the second remainder is obtained by dividing the first remainder by the second divisor.

Correct Option: A

Let number (dividend) be P.
∴  P = 296 × Q + 75 , where Q is the quotient and can have the values 1, 2, 3 etc.
P = 37 × 8 × Q + 37 × 2 + 1
P = 37 (8Q + 2) + 1
Thus we see that the remainder
is 1.
[Remark : From above it is clear
when the second divisor is a factor of the first divisor, the second remainder is obtained by dividing the first remainder by the second divisor.
Hence, divide 75 by 37, the remainder is 1].

Here, 52 is a multiple of 13.
Hence, the required remainder is obtained on dividing 45 by 13.

Correct Option: B

Here, 52 is a multiple of 13.
Hence, the required remainder is obtained on dividing 45 by 13.
Required remainder = 6.

Let assume the given number be P. Then,

	P ×	3			−		P ÷	3		= 10
		2						2

Correct Option: B

Let assume the given number be P. Then,

	P ×	3			−		P ÷	3		= 10
		2						2

As we know that when the second divisor is factor of first divisor, the second remainder is obtained by dividing the first remainder by the second divisor.

Correct Option: B

As we know that when the second divisor is factor of first divisor, the second remainder is obtained by dividing the first remainder by the second divisor.
Hence, on dividing 29 by 8, the remainder is 5.