(4)^2m gives 6 at unit digit.
(4)^{2m +1} gives 4 at unit digit.
(5)ⁿ gives 5 at unit place.

Correct Option: A

(4)^2m gives 6 at unit digit.
(4)^{2m +1} gives 4 at unit digit.
(5)ⁿ gives 5 at unit place.
The same is the case with 1.
∴  Required digit = Unit’s digit in the product of 4× 5 × 1 = 0

The digit in unit’s place = unit’s digit in the product 1 × 2 × 3 × 4 × 5 × 6 × 7 × 8 × 9
See the 5 and 8 from given unit place of product will multiply and give 0 at unit place.

Correct Option: A

The digit in unit’s place = unit’s digit in the product 1 × 2 × 3 × 4 × 5 × 6 × 7 × 8 × 9
See the 5 and 8 from given unit place of product will multiply and give 0 at unit place and then other unit place number will multiply with 0 and final number will be 0 at unit place.

Let us assume the 3 consecutive numbers are x, x + 1 and x + 2.
According to question,
∴  x + x + 1 + x + 2 = 51

Correct Option: D

Let us assume the 3 consecutive numbers are x, x + 1 and x + 2.
According to question,
∴  x + x + 1 + x + 2 = 51
⇒  3x + 3 = 51
⇒  3x = 51 – 3 = 48

Let us assume that six numbers are p, q, r, s, t, u.
According to the given question, Numbers are in decreasing order :
p > q > r > s > t > u
Again according to the question,
p + q + r + s + t = 5 × 30

q + r + s + t + u = 5 × 25

Correct Option: B

Let us assume that six numbers are p, q, r, s, t, u.
According to the given question, Numbers are in decreasing order :
p > q > r > s > t > u
Again according to the question,
p + q + r + s + t = 5 × 30
⇒ p + q + r + s + t = 150     --- (i)
q + r + s + t + u = 5 × 25
⇒ q + r + s + t + u = 125     --- (ii)
By equation (i) – (ii)
p – u = 150 – 125 = 25

Let us assume that the fraction is P.

Correct Option: C