Number System


  1. The unit’s digit in the product 771 × 663 × 365 is









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    71 = 7,
    72 = 49,
    73 = 343,
    74 = 2401
    31 = 3,
    32 = 9,
    33 = 27,
    34 = 81
    i.e. the digit at unit’s place gets repeated after power 4. Unit 6 remains same for any power.

    Correct Option: D

    71 = 7,
    72 = 49,
    73 = 343,
    74 = 2401
    31 = 3,
    32 = 9,
    33 = 27,
    34 = 81
    i.e. the digit at unit’s place gets repeated after power 4. Unit 6 remains same for any power.
    ∴  Required unit’s digit
    = Unit’s digit in the product of 73 × 6 × 1 = 4


  1. The unit digit in the product (122)173 is









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    21 = 2
    22 = 4
    23 = 8
    24 = 16
    25 = 32
    Now As we know that,
    Unit place of 21 = 2
    Unit place of 22 = 4
    Unit place of 23 = 8
    Unit place of 24 = 6
    Unit place of 25 = 2
    i.e. 2 repeats itself after the index 4.

    Correct Option: A

    21 = 2
    22 = 4
    23 = 8
    24 = 16
    25 = 32
    Now As we know that,
    Unit place of 21 = 2
    Unit place of 22 = 4
    Unit place of 23 = 8
    Unit place of 24 = 6
    Unit place of 25 = 2
    i.e. 2 repeats itself after the index 4.
    ∴  Unit digit in the product of (122)173
    = Unit digit in (122)1 = 2
    (1 = remainder when 173 is divided by 4).



  1. One’s digit of the number (22)23 is









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    Unit’s digit in the expansion of (22)23 = Unit’s digit in the expansion of (2)23
    21 = 2
    22 = 4
    23 = 8
    24 = 16
    25 = 32

    Correct Option: C

    Unit’s digit in the expansion of (22)23 = Unit’s digit in the expansion of (2)23
    21 = 2
    22 = 4
    23 = 8
    24 = 16
    25 = 32
    Now As we know that,
    Unit place of 21 = 2
    Unit place of 22 = 4
    Unit place of 23 = 8
    Unit place of 24 = 6
    Unit place of 25 = 2
    i.e. 2 repeats itself after the index 4.
    On dividing 23 by 4, remainder = 3
    ∴  Unit’s digit in (2)23 = Unit’s digit in (2)3 = 8


  1. The last digit of 340 is









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    31 = 3;
    32 = 9;
    33 = 27;
    34 = 81;
    35 = 343 ; ...........................................
    We can write 340 as below,
    340 = 34 x 34 x ........ 10 times
    Unit place digit for 340 = Unit place Digit of 34 x Unit place Digit of 34 x.......... 10 times

    Correct Option: A

    31 = 3;
    32 = 9;
    33 = 27;
    34 = 81;
    35 = 343 ; ...........................................
    We can write 340 as below,
    340 = 34 x 34 x ........ 10 times
    Unit place digit for 340 = Unit place Digit of 34 x Unit place Digit of 34 x.......... 10 times
    Unit place digit for 340 = 1 x 1 x............. 10 times
    ∴  Unit’s digit in 340 = 1



  1. Unit digit in (264)102 + (264)103 is :









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    Unit digit in (264)4 4 × 4 × 4 × 4 is 6
    ∴  Unit digit in (264)100 is also 6.
    Now, (264)102 = (264)100 × (264)2
    = (Unit digit 6) × (Unit digit 6) = 36
    ∴  Unit digit is 6

    Correct Option: A

    Unit digit in (264)4 4 × 4 × 4 × 4 is 6
    ∴  Unit digit in (264)100 is also 6.
    Now, (264)102 = (264)100 × (264)2
    = (Unit digit 6) × (Unit digit 6) = 36
    ∴  Unit digit is 6
    Similarly

    Therefore, the unit digit in (264)102 + (264)103 is 6 + 4 = 10 i.e. 0.