Number System
- The sum of the two position number P and Q is 2.5 time their difference .If the product of the number 84 then the what is the sum of those two number?
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Let the number be P and Q
According to the question
(P + Q) = 2.5 (P - Q)
⇒ P + Q = 2.5P - 25Q
⇒ 3.5Q = 1.5P
⇒ P / Q = 7/3 .....(i)
Now PQ = 84Correct Option: D
Let the number be P and Q
According to the question
(P + Q) = 2.5 (P - Q)
⇒ P + Q = 2.5P - 25Q
⇒ 3.5Q = 1.5P
⇒ P / Q = 7/3 .....(i)
Now PQ = 84
⇒ Q2 = (84 x 3) / 7
⇒ Q2 = 36
∴ Q = 6
&ther4; P = (7/3) x 6 = 14
Sum of the number = P + Q = 14 + 6 = 20
- Out of three given number the first number is twice the second and thrice number is 154 then what is the difference between the first and third number ?
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Let the third number = N
Then the first number = 3N
And second number = 3N/2
According to the question [N + 3N + 3N/2] / 3=154Correct Option: C
Let the third number = N
Then the first number = 3N
And second number = 3N/2
According to the question [N + 3N + 3N/2] / 3=154
⇒ (2N +6N +3N) / 6 = 154
∴ N = (154 x 6) / 11 = 84
∴ Required difference = 3N - N = 2N
= 2 x 84 = 168
- Find the maximum number of tree which can plant 20 m apart on the two side of straight road 1760 m long
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Number of trees that can be planted on one side of road = (1760 / 20) + 1
Correct Option: D
Number of trees that can be planted on one side of road = (1760 / 20) + 1
= 88 + 1
=89
∴ Trees on the both side = 2 x 89=178
- The difference between two number is 18 if four times the second number is less then three what is the sum these two number?
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Let first number = P
And second number = Q
According to the question
P - Q = 10 ....(i)
And 3P - 4Q = 18...(ii)
on multiply eq (i) by 3 and then subtract eq (ii) from it
3P - 3Q = 54
3P - 4Q = 18
Q = 36
On putting the value of Q in the eq (i)
P = 18 + Q = 18 +36
⇒ P = 54Correct Option: D
Let first number = P
And second number = Q
According to the question
P - Q = 10 ....(i)
And 3P - 4Q = 18...(ii)
on multiply eq (i) by 3 and then subtract eq (ii) from it
3P - 3Q = 54
3P - 4Q = 18
Q = 36
On putting the value of Q in the eq (i)
P = 18 + Q = 18 +36
⇒ P = 54
Required sum = P + Q = 54 +36 =90
- The smallest number of five digits exactly divisible by 476 is
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The smallest number of 5 digits = 10000
Now,Correct Option: D
The smallest number of 5 digits = 10000
Now,
∴ Required number = 10000 + (476 – 4)
= 10000 + 472 = 10472