The digit in the unit’s place of the product (2464)1793 × (615)317 × (131)491 is
0
2
3
5
Correct Option: A
(4)2m gives 6 at unit digit. (4)2m +1 gives 4 at unit digit. (5)n gives 5 at unit place. The same is the case with 1. ∴ Required digit = Unit’s digit in the product of 4× 5 × 1 = 0