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  1. One’s digit of the number (22)23 is
    1. 4
    2. 6
    3. 8
    4. 2
Correct Option: C

Unit’s digit in the expansion of (22)23 = Unit’s digit in the expansion of (2)23
21 = 2
22 = 4
23 = 8
24 = 16
25 = 32
Now As we know that,
Unit place of 21 = 2
Unit place of 22 = 4
Unit place of 23 = 8
Unit place of 24 = 6
Unit place of 25 = 2
i.e. 2 repeats itself after the index 4.
On dividing 23 by 4, remainder = 3
∴  Unit’s digit in (2)23 = Unit’s digit in (2)3 = 8



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