Electrical and electronics measurements miscellaneous


Electrical and electronics measurements miscellaneous

Electrical and Electronics Measurements

  1. In the two-wattmeter method of measuring power in a balanced three-phase circuit, one wattmeter shows zero and the other positive maximum. The load power factor is _________









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    The wattmeters reading is proportional to cos (30 + φ)
    Then other is proportional cos (30 – φ)
    Thus whenever load p.f. angle φ becomes 60°, one of the wattmeters would read zero.
    Hence for the given condition load load
    p.ƒ = cos 60° = 0.5

    Correct Option: A

    The wattmeters reading is proportional to cos (30 + φ)
    Then other is proportional cos (30 – φ)
    Thus whenever load p.f. angle φ becomes 60°, one of the wattmeters would read zero.
    Hence for the given condition load load
    p.ƒ = cos 60° = 0.5


  1. The internal resistance of a Weston standard cell is of the order of ___________Ω









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    NA

    Correct Option: C

    NA



  1. A 35 V dc supply is connected across a resistance of 600 ohm in series with an unknown resistance Rx. A voltmeter having a resistance of 1.2 k-ohm is connected across 600 ohm resistance and reads 5V. The value of resistance Rx will be _________kΩ









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    Voltage across R1, V1 = 35 – 5 = 30V

    Current in the circuit, I =
    E
    =
    1
    A
    600 × 1200
    400
    600 + 1200

    ∴ Rx =
    30 × 400
    = 2.4 kΩ
    5

    Correct Option: A

    Voltage across R1, V1 = 35 – 5 = 30V

    Current in the circuit, I =
    E
    =
    1
    A
    600 × 1200
    400
    600 + 1200

    ∴ Rx =
    30 × 400
    = 2.4 kΩ
    5


  1. A permanent magnet moving coil type ammeter and a moving iron type ammeter are connected in series in a resistive circuit fed from output of a half wave rectifier voltage source. If the moving iron type instrument reach 5 A, the permanent magnet moving coil type instrument is likely to read __________A









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    For half wave rectifier output,

    Idc =
    Im
    and Irms =
    Im
    π2

    Hence PMMC reading will be,
    Idc =
    2 × 5
    = 3.18 amp
    π

    Correct Option: A

    For half wave rectifier output,

    Idc =
    Im
    and Irms =
    Im
    π2

    Hence PMMC reading will be,
    Idc =
    2 × 5
    = 3.18 amp
    π



  1. A galvanometer is tested shown in figure, in the circuit, where E = 1.5 V, R1 = 1.0 ohm, R2 = 2500 ohm and R3 is variable. With R3 set at 450 ohm, the galvanometer deflection is 140 mm and with R3 set at 950 ohm, the galvanometer deflection is 70 mm. The resistance of t he galvanometer is ___________









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    It is simple resistive circuit calculation.

    Ic =
    1
    E
    1 + R3 + RG2500 +
    1(R3 + RG)
    1(R3 + RG)

    From the given data,
    1
    1
    1 + 450 + RG2500 +
    1(450 + RG)
    1(450 + RG)

    =
    1
    1
    1 + 450 + RG2500 +
    950 + RG
    1 + 950 + RG

    or 2500 (451 + RG) + 450 + RG = 2500 (951+ RG) + 50
    or 2501 RG = 2500 (951 – 902) + 50
    or RG = 49 ohms.

    Correct Option: C

    It is simple resistive circuit calculation.

    Ic =
    1
    E
    1 + R3 + RG2500 +
    1(R3 + RG)
    1(R3 + RG)

    From the given data,
    1
    1
    1 + 450 + RG2500 +
    1(450 + RG)
    1(450 + RG)

    =
    1
    1
    1 + 450 + RG2500 +
    950 + RG
    1 + 950 + RG

    or 2500 (451 + RG) + 450 + RG = 2500 (951+ RG) + 50
    or 2501 RG = 2500 (951 – 902) + 50
    or RG = 49 ohms.