Electrical and electronics measurements miscellaneous


Electrical and electronics measurements miscellaneous

Electrical and Electronics Measurements

  1. In the bridge given in the figure, the reading of the high impedance voltmeter is __________V









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    Current in either branch is

    I =
    10
    =
    1
    A
    303

    Vab = 20 ×
    1
    + 10 ×
    1
    = 3.33V
    33

    Correct Option: A

    Current in either branch is

    I =
    10
    =
    1
    A
    303

    Vab = 20 ×
    1
    + 10 ×
    1
    = 3.33V
    33


  1. Equal resistances of 100Ω each are connected in each arm of a Wheatstone bridge which is supplied by a 2 V battery source. The galvanometer of negligible resistance connected to the bridge can sense as low current as 1μs. The smallest value of resistance that can be measured is _________









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    NA

    Correct Option: A

    NA



  1. A unknown resistance is measured by substitution method. First a standard known resistance of 100Ω is connected in series with a circuit having a rheost at and a galvanometer. The battery voltage is 10 V and the setting of the rheostat is 500 Ω and the galvanometer shows a deflection of 60°. After this test, the battery voltage goes down to 9 V and when the unknown resistance is substituted for the known resistance, the galvanometer again shows a deflection of 60° with the same setting of the rheostat. The value of unknown resistance is _________









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    NA

    Correct Option: A

    NA


  1. A d.c voltmeter has a sensitivity of 1000Ω/ volt. When it measures half full scale in 100 V range, the current through the voltmeter will be ________mA









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    Sensitivity of d.c. voltmeter = 1000 Ω/volt For half scale in 100 V range, i.e. 50 V current through the voltmeter,

    I =
    50
    = 50mA
    1000

    Correct Option: A

    Sensitivity of d.c. voltmeter = 1000 Ω/volt For half scale in 100 V range, i.e. 50 V current through the voltmeter,

    I =
    50
    = 50mA
    1000



  1. The meter constant of a single-phase 240 V induction watthour meter is 400 r evolutions per kWh. The speed of the meter disc for a current of 10 amperes of 0.8 p.f. lagging will be ____________ rpm









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    n = k × power × time in hour

    =
    400 × 240 × 10 × 0.8
    ×
    1
    rph
    1003600

    = 12.8 rpm

    Correct Option: A

    n = k × power × time in hour

    =
    400 × 240 × 10 × 0.8
    ×
    1
    rph
    1003600

    = 12.8 rpm