Communication miscellaneous


  1. A carrier A cos ωct is modulated by a signal f(t) = 2 cos 104. 2πt + 5 cos 103. 2πt + 3 cos 104. 4πt, then the bandwidth of the FM signal will be—
    (Given that, kf = 15 × 103 Hz per volt)









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    We know that bandwidth of FM modulated signal is given by

    BW = 2(β + 1)fm =2Δf
    1 +
    1
    β

    Here, the maximum frequency component in f (t) is 20 kHz, and the maximum amplitude present in f (t) is 5 volt.
    Therefore the frequency deviation Δf is given by
    Δf = Kf ·Am = 15 × 103 × 5 = 75 kHz
    and the modulation index β is given by
    β =
    Δf
    =
    75 kHz
    =
    7.5
    = 3.75
    fm20kHz2

    Now, BW = 2 (β + 1) fm = 2(3·75 + 1) 20 kHz
    = 9·5 × 20 kHz = 190 kHz
    Hence alternative (B) is the correct choice.

    Correct Option: B

    We know that bandwidth of FM modulated signal is given by

    BW = 2(β + 1)fm =2Δf
    1 +
    1
    β

    Here, the maximum frequency component in f (t) is 20 kHz, and the maximum amplitude present in f (t) is 5 volt.
    Therefore the frequency deviation Δf is given by
    Δf = Kf ·Am = 15 × 103 × 5 = 75 kHz
    and the modulation index β is given by
    β =
    Δf
    =
    75 kHz
    =
    7.5
    = 3.75
    fm20kHz2

    Now, BW = 2 (β + 1) fm = 2(3·75 + 1) 20 kHz
    = 9·5 × 20 kHz = 190 kHz
    Hence alternative (B) is the correct choice.


  1. Following is not advantage of FM over AM—









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    NA

    Correct Option: D

    NA



  1. The message carrying efficiency is best in—









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    NA

    Correct Option: C

    NA


  1. Which one is an advantage of AM over FM?









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    The main advantage of AM over FM is that in a given frequency space, FM accommodates less number of channels as compared to AM.

    Correct Option: C

    The main advantage of AM over FM is that in a given frequency space, FM accommodates less number of channels as compared to AM.



  1. Figure of merit is always unity in—









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    NA

    Correct Option: A

    NA