Communication miscellaneous
- A carrier A cos ωct is modulated by a signal f(t) = 2 cos 104. 2πt + 5 cos 103. 2πt + 3 cos 104. 4πt, then the bandwidth of the FM signal will be—
(Given that, kf = 15 × 103 Hz per volt)
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We know that bandwidth of FM modulated signal is given by
BW = 2(β + 1)fm =2Δf 1 + 1 β
Here, the maximum frequency component in f (t) is 20 kHz, and the maximum amplitude present in f (t) is 5 volt.
Therefore the frequency deviation Δf is given by
Δf = Kf ·Am = 15 × 103 × 5 = 75 kHz
and the modulation index β is given byβ = Δf = 75 kHz = 7.5 = 3.75 fm 20kHz 2
Now, BW = 2 (β + 1) fm = 2(3·75 + 1) 20 kHz
= 9·5 × 20 kHz = 190 kHz
Hence alternative (B) is the correct choice.Correct Option: B
We know that bandwidth of FM modulated signal is given by
BW = 2(β + 1)fm =2Δf 1 + 1 β
Here, the maximum frequency component in f (t) is 20 kHz, and the maximum amplitude present in f (t) is 5 volt.
Therefore the frequency deviation Δf is given by
Δf = Kf ·Am = 15 × 103 × 5 = 75 kHz
and the modulation index β is given byβ = Δf = 75 kHz = 7.5 = 3.75 fm 20kHz 2
Now, BW = 2 (β + 1) fm = 2(3·75 + 1) 20 kHz
= 9·5 × 20 kHz = 190 kHz
Hence alternative (B) is the correct choice.
- Following is not advantage of FM over AM—
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NA
Correct Option: D
NA
- The message carrying efficiency is best in—
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NA
Correct Option: C
NA
- Which one is an advantage of AM over FM?
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The main advantage of AM over FM is that in a given frequency space, FM accommodates less number of channels as compared to AM.
Correct Option: C
The main advantage of AM over FM is that in a given frequency space, FM accommodates less number of channels as compared to AM.
- Figure of merit is always unity in—
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NA
Correct Option: A
NA