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A carrier A cos ωct is modulated by a signal f(t) = 2 cos 104. 2πt + 5 cos 103. 2πt + 3 cos 104. 4πt, then the bandwidth of the FM signal will be—
(Given that, kf = 15 × 103 Hz per volt)
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- 170 kHz
- 190 kHz
- 210 kHz
- 150 kHz
- 170 kHz
Correct Option: B
We know that bandwidth of FM modulated signal is given by
BW = 2(β + 1)fm =2Δf | 1 + | |||
β |
Here, the maximum frequency component in f (t) is 20 kHz, and the maximum amplitude present in f (t) is 5 volt.
Therefore the frequency deviation Δf is given by
Δf = Kf ·Am = 15 × 103 × 5 = 75 kHz
and the modulation index β is given by
β = | = | = | = 3.75 | |||
fm | 20kHz | 2 |
Now, BW = 2 (β + 1) fm = 2(3·75 + 1) 20 kHz
= 9·5 × 20 kHz = 190 kHz
Hence alternative (B) is the correct choice.