Ratio, Proportion
- In an alloy, the ratio of copper and zinc is 5 : 2. If 1.250 kg of zinc is mixed in 17 kg 500 g of
alloy, then the ratio of copper and zinc will be
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Weight of copper in 17kg 500 gm i.e. 17500 gm of alloy
= 5 × 17500 = 12500 gm 7
Weight of zinc = (17500 – 12500)
= 5000 gm
1250 gm of zinc is mixed in alloy.
∴ Total weight of zinc
= 1250 + 5000 = 6250 gm.
∴ Required ratio
= 12500 : 6250 = 2 : 1Correct Option: A
Weight of copper in 17kg 500 gm i.e. 17500 gm of alloy
= 5 × 17500 = 12500 gm 7
Weight of zinc = (17500 – 12500)
= 5000 gm
1250 gm of zinc is mixed in alloy.
∴ Total weight of zinc
= 1250 + 5000 = 6250 gm.
∴ Required ratio
= 12500 : 6250 = 2 : 1
- Four years ago, the ratio of A’s age to B’s age was 11 : 14 and four years later their age will be in the ratio 13 : 16. The present age of A is
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Let the age of A and B four years ago be 11x and 14x years respectively.
According to the question,
After 4 years from now,11x + 8 = 13 14x + 8 16
⇒ 176x + 128 = 182x + 104
⇒ 182x – 176x = 128 – 104⇒ 6x = 24 ⇒ x = 24 = 4 6
∴ A’s present age = (11x + 4) years
= 11 × 4 + 4 = 48 yearsCorrect Option: A
Let the age of A and B four years ago be 11x and 14x years respectively.
According to the question,
After 4 years from now,11x + 8 = 13 14x + 8 16
⇒ 176x + 128 = 182x + 104
⇒ 182x – 176x = 128 – 104⇒ 6x = 24 ⇒ x = 24 = 4 6
∴ A’s present age = (11x + 4) years
= 11 × 4 + 4 = 48 years
- If x : y = 3 : 4 and y : z = 3 : 4,
then x + y + z is equal to 3z
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x : y = 3 : 4 = 9 : 12
y : z = 3 : 4 = 12 : 16
∴ x : y : z = 9 : 12 : 16∴ x + y + z = 9k + 12k + 16k 3z 3 × 16k = 37 48 Correct Option: D
x : y = 3 : 4 = 9 : 12
y : z = 3 : 4 = 12 : 16
∴ x : y : z = 9 : 12 : 16∴ x + y + z = 9k + 12k + 16k 3z 3 × 16k = 37 48
- A person distributes his pens among four friends A, B, C, D in the ratio
that the person should have?= 1 : 1 : 1 : 1 What is the minimum number of pens 3 4 5 6
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A : B : C
= 1 : 1 : 1 : 1 3 4 5 6 = 1 × 60 : 1 × 60 : 1 × 60 : 1 × 60 3 4 5 6
[LCM of 3, 4, 5 & 6 = 60]
= 20 : 15 : 12 : 10
∴ Minimum number of pens
= 20 + 15 + 12 + 10 = 57Correct Option: A
A : B : C
= 1 : 1 : 1 : 1 3 4 5 6 = 1 × 60 : 1 × 60 : 1 × 60 : 1 × 60 3 4 5 6
[LCM of 3, 4, 5 & 6 = 60]
= 20 : 15 : 12 : 10
∴ Minimum number of pens
= 20 + 15 + 12 + 10 = 57
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then (a + b) : (b + c) = ?If a − 2 and b − 4 b 3 c 5
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a : b = 2 : 3
b : c = 4 : 5
∴ a : b : c = 2 × 4 : 3 × 4 : 3 × 5
= 8 : 12 : 15∴ a + b = 8 + 12 = 20 b + c 12 + 15 27
= 20 : 27Correct Option: D
a : b = 2 : 3
b : c = 4 : 5
∴ a : b : c = 2 × 4 : 3 × 4 : 3 × 5
= 8 : 12 : 15∴ a + b = 8 + 12 = 20 b + c 12 + 15 27
= 20 : 27