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A person distributes his pens among four friends A, B, C, D in the ratio
that the person should have?= 1 : 1 : 1 : 1 What is the minimum number of pens 3 4 5 6
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- 57
- 65
- 75
- 45
Correct Option: A
A : B : C
= | : | : | : | ||||
3 | 4 | 5 | 6 |
= | × 60 : | × 60 : | × 60 : | × 60 | ||||
3 | 4 | 5 | 6 |
[LCM of 3, 4, 5 & 6 = 60]
= 20 : 15 : 12 : 10
∴ Minimum number of pens
= 20 + 15 + 12 + 10 = 57