Ratio, Proportion
- In an alloy, the ratio of copper and zinc is 5 : 2. If 1.250 kg of zinc is mixed in 17 kg 500 g of
alloy, then the ratio of copper and zinc will be
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Weight of copper in 17kg 500 gm i.e. 17500 gm of alloy
= 5 × 17500 = 12500 gm 7
Weight of zinc = (17500 – 12500)
= 5000 gm
1250 gm of zinc is mixed in alloy.
∴ Total weight of zinc
= 1250 + 5000 = 6250 gm.
∴ Required ratio
= 12500 : 6250 = 2 : 1Correct Option: A
Weight of copper in 17kg 500 gm i.e. 17500 gm of alloy
= 5 × 17500 = 12500 gm 7
Weight of zinc = (17500 – 12500)
= 5000 gm
1250 gm of zinc is mixed in alloy.
∴ Total weight of zinc
= 1250 + 5000 = 6250 gm.
∴ Required ratio
= 12500 : 6250 = 2 : 1
- Alcohol and water in two vessels A and B are in the ratio 5 : 3 and 5 : 4 respectively. In what ratio, the liquids in both the vessels be mixed to obtain a new mixture in vessel C in the ratio 7 : 5 ?
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By Alligation Rule
∴ Ratio = 1 : 1 36 24
= 3 : 2Correct Option: B
By Alligation Rule
∴ Ratio = 1 : 1 36 24
= 3 : 2
- A sum of money is divided among A, B, C and D in the ratio of 3 : 7 : 9 : 13 . If the share of B is ₹, then what will be the total amount of money of A and C together ?
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Let A's share = 3N
B's share = 9N
and D's share = 13N
According to the question
7N = 4872
∴ N = 4872/7 = 696
Share of A and C = 3N + 9N = 12NCorrect Option: A
Let A's share = 3N
B's share = 9N
and D's share = 13N
According to the question
7N = 4872
∴ N = 4872/7 = 696
Share of A and C = 3N + 9N = 12N
= 12 x 696 = ₹ 8352
- A sum of ₹ 7000 is divided among A, B, and C in such a way that the shares of A and B are in the ratio 2 : 3 and those of B and C are in the ratio 4 : 5, The ahare of B is
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Given, A : B = 2 : 3
and B : C = 4 : 5
Then, A : B : C = 8 : 12 : 15
7there4; Share of B = [12/(8 + 12 + 15)] x 7000Correct Option: C
Given, A : B = 2 : 3
and B : C = 4 : 5
Then, A : B : C = 8 : 12 : 15
7there4; Share of B = [12/(8 + 12 + 15)] x 7000
= (12 x 7000)/35
= 2400
= ₹ 2400
- The quantity that must be added to each term of a : b, so as to make it c : d, is
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Let the quantity be k.
Then, (a + k) / (b + k) = c/dCorrect Option: D
Let the quantity be k.
Then, (a + k) / (b + k) = c/d
⇒ (a + k)d = (b + k)c
⇒ ad + dk = bc + ck
⇒ ad - bc = ck - dk
⇒ ad - bc = k(c - d)
∴ k = (ad - bc) / (c - d)