Ratio, Proportion
- ₹ 5625 are divided among A, B and C so that A receives 1/2 as much as B and C together receive and B receives 1/4 as much as A and C together receive. Find the sum of shares of A and B.
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Accoridng to rhe question
A = ( B + C)/2
⇒ B + C = 2A
⇒ A + B + C = 3A (adding A on both sides)
∴ 3A = 5625
∴ A = 5625/3 = ₹ 1875 ....(i)
Again from question B = (A + C)/4
⇒ A + C = 4B
⇒ A + B + C = 5B (adding B on both sides)
⇒ 5B = 5625
∴ B = 5624/5 = ₹ 1125 ...(ii)Correct Option: B
Accoridng to rhe question
A = ( B + C)/2
⇒ B + C = 2A
⇒ A + B + C = 3A (adding A on both sides)
∴ 3A = 5625
∴ A = 5625/3 = ₹ 1875 ....(i)
Again from question B = (A + C)/4
⇒ A + C = 4B
⇒ A + B + C = 5B (adding B on both sides)
⇒ 5B = 5625
∴ B = 5624/5 = ₹ 1125 ...(ii)
From (i) and (ii)
⇒ A + B = 1875 + 1125 = ₹ 3000
- ₹ 710 were divided among A, B and C in such a way that A had ₹ 40 more than B and C had ₹ 30 more than A. How much was C's share?
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Let B gets x.
Then, A gets (x + 40) and C gets (x + 70).
According to the question,
x + 40 + x + x + 70 = 710
Correct Option: A
Let B gets x.
Then, A gets (x + 40) and C gets (x + 70).
According to the question,
x + 40 + x + x + 70 = 710
⇒ 3x = 710 - 110 = 600
∴ x = 600/3 = 200
∴ C's share = 200 + 70 = ₹ 270
- The ratio of 1st and 2nd classes train fairs between two stations is 3 : 1 and that of the number of passengers travelling between these stations by 1st and 2nd classes is 1 : 50. If on a particular day, ₹ 2650 be collected from the passengers travelling between these stations, then find the amount collected from 2nd class passengers.
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Ratio of the amounts collected from 1st and 2nd classes fairs = (3 x 1) ; (1 x 50) = 3 : 50
∴ Amount collected from 2nd class
Passengers = 2650 x (50/53) = ₹ 2500Correct Option: D
Ratio of the amounts collected from 1st and 2nd classes fairs = (3 x 1) ; (1 x 50) = 3 : 50
∴ Amount collected from 2nd class
Passengers = 2650 x (50/53) = ₹ 2500
- Out of two sections A and B, 10 students of section B shift to A, as a result strength of A becomes 3 times the strength of B. But , if 10 students shift over from A to B, both A and B become equal in strength. Ratio of the number of students in section A that of section B is ?
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A +10 = 3(B - 10)
⇒ A - 3B = -20 ....(i)
And ( A - 10) = (B + 10)
⇒ A - B = 20 ...(ii)
on subtracting Eq.(ii) from Eq.(i), we get
(A - 3B) - (A - B) = -20 - 20
⇒ - 2B = - 40
there4; B = 20Correct Option: A
A +10 = 3(B - 10)
⇒ A - 3B = -20 ....(i)
And ( A - 10) = (B + 10)
⇒ A - B = 20 ...(ii)
on subtracting Eq.(ii) from Eq.(i), we get
(A - 3B) - (A - B) = -20 - 20
⇒ - 2B = - 40
there4; B = 20
Now, by using Eq. ...(ii),
there4; Ratio of the numbers of students of A and B = 40 : 20 = 2 : 1
- A sum of money is to be divided equally among P, Q and R in the respective ratio of 5 : 6 : 7 and another sum of money is to be divided between S and T equally. If S got ₹ 2100 less than P, then how much amount did Q receive?
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Couldn't be determined, since the total amount of money is not given in either of the case.
Correct Option: D
Couldn't be determined, since the total amount of money is not given in either of the case