Problem on Trains
- How long will a train 130 m long travelling at 40 km an hour, take to pass a kilometer stone ?
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Total distance = 130 m = 0.13 km
Speed of the train = 40 km /hrCorrect Option: B
Total distance = 130 m = 0.13 km
Speed of the train = 40 km /hr
Time taken = 0.13/40 hr = (0.13 x 60 x 60) / 40 = 11.7 sec.
- A train 300 m long crossed a platform 900 m long in 1 minute 12 seconds. The speed of the train in km/hr was ?
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Distance covered in 72 sec. = (300 + 900) m
Correct Option: D
Distance covered in 72 sec. = 300 + 900 m
∴ Speed = 1200/72 = 50/3 m/sec. = 60 km/hr .
- Two trains 132 metres and 108 metres long are running in opposite directions, one at the rate of 32 kmph and another one at the rate of 40 kmph. From the moment they meet they will cross each other in ?
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Relative speed of both trains = (32 + 40) = 72 km/hr = 72 x (5/18) = 20 m/sec
Distance covered in crossing each other = 132 + 108 = 240 mCorrect Option: C
Relative speed of both trains = (32 + 40) = 72 km/hr = 72 x (5/18) = 20 m/sec
Distance covered in crossing each other = 132 + 108 = 240 m
∴ Required time = 240/20 = 12 sec.
- Two trains of equals length are running on parallel line in the same direction at the rate of 46 kmph and 36 kmph. The faster train passes the slower train in 36 seconds. The length of each train is ?
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Let the length of each train = L metres
Relative speed = (46 - 36) = 10 km/hr. = 10 x (5/18) = 25/9 m/sec
Distance covered in crossing = (L + L) = 2L metresCorrect Option: A
Let the length of each train = L metres
Relative speed = (46 - 36) = 10 km/hr. = 10 x (5/18) = 25/9 m/sec
Distance covered in crossing = (L + L) = 2L metres
⇒ 2L x (9/25) = 36
∴ L = (25 x 36)/(2 x 9) = 50 metres.
- A train crosses a platform 100 metres long in 60 seconds at a speed of 45 km per hour. The time taken by the train to cross an electric pole is ?
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Let the length of train = L metres
Speed of train = 45 x (5/18) = 25/2 m/sec.
Distance covered in crossing the platform = (L + 100) m
∴ (L + 100) x (2/25) = 60Correct Option: C
Let the length of train = L metres
Speed of train = 45 x (5/18) = 25/2 m/sec.
Distance covered in crossing the platform = (L + 100) m
∴ (L + 100) x (2/25) = 60
⇒ 2L + 200 = 1500
⇒ L = 650.
Now, time taken to cross the pole = 650 x (2/25) = 52 sec.