Let the trains meet after time t at a distance x from station N.
Then another train coming from station M covers a distance of (x + 50)

Correct Option: B

Let the trains meet after time t at a distance x from station N.
Then another train coming from station M covers a distance of (x + 50)

For station M,
(x + 50) = 125t
⇒ x = 125t - 50 ..(i)

For station N,
x = 75t .....(ii)

From Eqs. (i) and (ii), we get
75t = 125t - 50
⇒ t = 1h

Distance between station M and N = 125 + 75t = 200 x 1 = 200 km

Because of stoppages, train covers 50 km less per hour.
∴ Time taken taken to cover 50 km = 50/150 h = (50/150) x 60 = 20 min

Correct Option: A

Because of stoppages, train covers 50 km less per hour.
∴ Time taken taken to cover 50 km = 50/150 h = (50/150) x 60 = 20 min

Because of stoppages, train covers 18 km less per hour .
∴ Time taken to cover 18 km = 18/108

Correct Option: C

Because of stoppages, train covers 18 km less per hour .
∴ Time taken to cover 18 km = 18/108 = 1/6 h = (1/6) x 60 = 10 min

Let the speeds of two trains be x and y, respectively .
∴ Length of 1st train = 54x
Length of the 2nd train = 34y
According to the question.
(54x + 34y) / (x + y) = 46

Correct Option: A

Let the speeds of two trains be x and y, respectively .
∴ Length of 1st train = 54x
Length of the 2nd train = 34y
According to the question.
(54x + 34y) / (x + y) = 46
⇒ 54x + 34y = 46x + 46y
⇒ 27x + 17y = 23x + 23y
⇒ 4x = 6y
⇒ x/y = 3/2
∴ x : y = 3 : 2

Let speed of 1st train be 8S and speed of 2nd train be 9S
According to the question.
Speed of second train = 360/4 = 90 km/h
9S = 90
⇒ S = 10
So, speed of 1st train = 8 x 10 = 80 km/h

Correct Option: A

Let speed of 1st train be 8S and speed of 2nd train be 9S
According to the question.
Speed of second train = 360/4 = 90 km/h
9S = 90
⇒ S = 10
So, speed of 1st train = 8 x 10 = 80 km/h
∴ Required distance = 80 x 3 = 240 km