Problem on Trains

Problem on Trains

Easy Questions
Moderate Questions
Difficult Questions
Problem on Trains Tutorial

Aptitude

Simplification
Number System
Fractions
Elementary Algebra
LCM and HCF
Approximation
Unitary Method
Linear Equation
Quadratic Equation
Discount
Average
Surds and Indices
Percentage
Square root and cube root
Order of Magnitude
Work and Wages
Odd Man Out and Series
Algebra
Profit and Loss
Stocks and Shares
True Discount
Ratio, Proportion
Partnership
Alligation or Mixture
Time and Work
Pipes and Cistern
Speed, Time and Distance
Problem on Trains
Height and Distance
Banker's Discount
Boats and Streams
Races and games
Problems on Ages
Clocks and Calendars
Simple interest
Compound Interest
Sets and Functions
Area and Perimeter
Volume and Surface Area of Solid Figures
Sequences and Series
Plane Geometry
Logarithm
Probability
Permutation and Combination
Statistics
Mensuration
Trigonometry
Aptitude miscellaneous
  1. A 400 m long train takes 36 s to cross a man walking at 20 km/h in the direction opposite to that of the train. What is the speed of the train ?








  1. View Hint View Answer Discuss in Forum

    Relative speed of train = 400/36 m/s = 400/36 x (18/5) = 40 km/h
    Relative speed of train = Speed of train + Speed of man

    Correct Option: A

    Relative speed of train = 400/36 m/s = 400/36 x (18/5) = 40 km/h
    Relative speed of train = Speed of train + Speed of man
    ⇒ 40 = Speed of train + 20
    ∴ Speed of train = 40 - 20 = 20 km/h

  1. Two train of length 70 m and 90 m are moving in opposite directions at 10 m/s and 6 m/s, respectively. Find the time taken by trains to cross each other . ?








  1. View Hint View Answer Discuss in Forum

    According to the formula .
    Required time = (x + y) / (u + v)
    Here, x = 70 m, y = 90 m, u = 10 m/s and v = 6 m/s

    Correct Option: A

    According to the formula .
    Required time = (x + y) / (u + v)
    Here, x = 70 m, y = 90 m, u = 10 m/s and v = 6 m/s
    ∴ Required time = (70 + 90) / (10 + 6) = 160/16 = 10 s

  1. A train travelling with uniform speed crosses two bridges of lengths 300 m and 240 m in 21 s and 18 s respectively. Find the speed of the train?








  1. View Hint View Answer Discuss in Forum

    Let length of the train = L
    According to the question,
    (L + 300)/21 = (L + 240)/18

    Correct Option: A

    Let length of the train = L
    According to the question,
    (L + 300)/21 = (L + 240)/18
    ⇒ (L + 300)/7 = (L + 240)/6
    ⇒ 6L + 1800 = 7L + 1680
    ∴ L = 120 m

    Taking the length of the 2nd bridge into consideration,
    Speed of train = (L+ 240)/18 = (120 + 240)/18 m/s
    = (360/18) x (18/5) km/h
    = 72 km/h

  1. The lengths of a train and a platform are equal. If a train running at a speed of 90 km/h, crossed the platform in 1min, then find the length of the train. ?








  1. View Hint View Answer Discuss in Forum

    Let length of both train and platform be L.
    Distance covered by the train to cross the platform = L + L = 2L
    Time =1 min = 60 s
    and speed = 90 km/h = 90 x 5/18 = 25 m/s
    ∴ Distance = Speed x Time

    Correct Option: D

    Let length of both train and platform be L.
    Distance covered by the train to cross the platform = L + L = 2L
    Time =1 min = 60 s
    and speed = 90 km/h = 90 x 5/18 = 25 m/s
    ∴ Distance = Speed x Time
    ⇒ 2L = 25 x 60
    ⇒ L = 750 m

  1. A train moving with uniform speed crosses a pole in 2 s and a 250 m long bridge in 7 s. Find the length of the train?








  1. View Hint View Answer Discuss in Forum

    Let length of the train be L m.
    According to the question,
    L/2 = (L + 250)/7

    Correct Option: C

    Let length of the train be L m.
    According to the question,
    L/2 = (L + 250)/7
    ⇒ 7L = 2L + 500
    ⇒ 7L - 2L = 500
    ⇒ 5L = 500
    ∴ L = 500/5 = 100 m