Problem on Trains
- From station M and N, two trains start moving towards each other at speed 125 km/h and 75 km/h, respectively. When the two trains meet each other, it is founds that one train covers 50 km more than another. Find the distance between M and N. ?
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Let the trains meet after time t at a distance x from station N.
Then another train coming from station M covers a distance of (x + 50)Correct Option: B
Let the trains meet after time t at a distance x from station N.
Then another train coming from station M covers a distance of (x + 50)
For station M,
(x + 50) = 125t
⇒ x = 125t - 50 ..(i)
For station N,
x = 75t .....(ii)
From Eqs. (i) and (ii), we get
75t = 125t - 50
⇒ t = 1h
Distance between station M and N = 125 + 75t = 200 x 1 = 200 km
- Excluding stoppages, the speed of a train is 108 km/h and including stoppages, it is 90 km/h. For how many minute does the train stop per hour ?
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Because of stoppages, train covers 18 km less per hour .
∴ Time taken to cover 18 km = 18/108Correct Option: C
Because of stoppages, train covers 18 km less per hour .
∴ Time taken to cover 18 km = 18/108 = 1/6 h = (1/6) x 60 = 10 min
- Without stoppages, the speed of a train is 150 km/h and with stoppages, it is 100 km/h. How many minutes does the train stop ?
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Because of stoppages, train covers 50 km less per hour.
∴ Time taken taken to cover 50 km = 50/150 h = (50/150) x 60 = 20 minCorrect Option: A
Because of stoppages, train covers 50 km less per hour.
∴ Time taken taken to cover 50 km = 50/150 h = (50/150) x 60 = 20 min
- Two trains running in opposite directions cross a man standing on the platform 54s and 34s respectively and they cross each other in 46 s . Find the ratio of their speeds. ?
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Let the speeds of two trains be x and y, respectively .
∴ Length of 1st train = 54x
Length of the 2nd train = 34y
According to the question.
(54x + 34y) / (x + y) = 46Correct Option: A
Let the speeds of two trains be x and y, respectively .
∴ Length of 1st train = 54x
Length of the 2nd train = 34y
According to the question.
(54x + 34y) / (x + y) = 46
⇒ 54x + 34y = 46x + 46y
⇒ 27x + 17y = 23x + 23y
⇒ 4x = 6y
⇒ x/y = 3/2
∴ x : y = 3 : 2
- Two trains are running 40 km/h and 20 km/h respectively, in the same directions. The fast train completely passes a man sitting in the slow train in 5 s. The length of the fast a train is ?
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The length of the fast train = Relative speed x Time
= (40 - 20) x (5/18) x 5Correct Option: C
The length of the fast train = Relative speed x Time
= (40 - 20) x (5/18) x 5 = 277/9 m