Problem on Trains
- The lengths of a train and a platform are equal. If a train running at a speed of 90 km/h, crossed the platform in 1min, then find the length of the train. ?
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Let length of both train and platform be L.
Distance covered by the train to cross the platform = L + L = 2L
Time =1 min = 60 s
and speed = 90 km/h = 90 x 5/18 = 25 m/s
∴ Distance = Speed x TimeCorrect Option: D
Let length of both train and platform be L.
Distance covered by the train to cross the platform = L + L = 2L
Time =1 min = 60 s
and speed = 90 km/h = 90 x 5/18 = 25 m/s
∴ Distance = Speed x Time
⇒ 2L = 25 x 60
⇒ L = 750 m
- Two train of length 70 m and 90 m are moving in opposite directions at 10 m/s and 6 m/s, respectively. Find the time taken by trains to cross each other . ?
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According to the formula .
Required time = (x + y) / (u + v)
Here, x = 70 m, y = 90 m, u = 10 m/s and v = 6 m/sCorrect Option: A
According to the formula .
Required time = (x + y) / (u + v)
Here, x = 70 m, y = 90 m, u = 10 m/s and v = 6 m/s
∴ Required time = (70 + 90) / (10 + 6) = 160/16 = 10 s
- A train travelling with uniform speed crosses two bridges of lengths 300 m and 240 m in 21 s and 18 s respectively. Find the speed of the train?
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Let length of the train = L
According to the question,
(L + 300)/21 = (L + 240)/18Correct Option: A
Let length of the train = L
According to the question,
(L + 300)/21 = (L + 240)/18
⇒ (L + 300)/7 = (L + 240)/6
⇒ 6L + 1800 = 7L + 1680
∴ L = 120 m
Taking the length of the 2nd bridge into consideration,
Speed of train = (L+ 240)/18 = (120 + 240)/18 m/s
= (360/18) x (18/5) km/h
= 72 km/h
- A 400 m long train takes 36 s to cross a man walking at 20 km/h in the direction opposite to that of the train. What is the speed of the train ?
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Relative speed of train = 400/36 m/s = 400/36 x (18/5) = 40 km/h
Relative speed of train = Speed of train + Speed of manCorrect Option: A
Relative speed of train = 400/36 m/s = 400/36 x (18/5) = 40 km/h
Relative speed of train = Speed of train + Speed of man
⇒ 40 = Speed of train + 20
∴ Speed of train = 40 - 20 = 20 km/h
- A train moving with uniform speed crosses a pole in 2 s and a 250 m long bridge in 7 s. Find the length of the train?
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Let length of the train be L m.
According to the question,
L/2 = (L + 250)/7Correct Option: C
Let length of the train be L m.
According to the question,
L/2 = (L + 250)/7
⇒ 7L = 2L + 500
⇒ 7L - 2L = 500
⇒ 5L = 500
∴ L = 500/5 = 100 m