Problem on Trains

Problem on Trains

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Aptitude miscellaneous
  1. A train 280 m long is moving at a speed of 60 km/hr. The time taken by the train to cross a platform 220 m long is ?








  1. View Hint View Answer Discuss in Forum

    Distance covered = 220 + 280 = 500 = 0.5 km
    Speed = 60 kmph.

    Correct Option: C

    Distance covered = 220 + 280 = 500 = 0.5 km
    Speed = 60 kmph.

    Time taken = 0.5 / 60 hr = (0.5 x 60 x 60)/60 sec
    = 30 sec

  1. A train 150 m long passes a telegraphs post in 12 seconds. Find in what time, it will pass a bridge 250 m long ?








  1. View Hint View Answer Discuss in Forum

    ∵ Speed of the train = 150/12 m/sec.
    Required time taken to cross the bridge = [(150 + 250) x (12/150)]

    Correct Option: A

    ∵ Speed of the train = 150/12 m/sec.
    Required time taken to cross the bridge = [(150 + 250) x (12/150)] = 32 sec.

  1. A train 200 m long is running with a speed of 72 km/hr. In what time will it pass a platform 160 m long ?








  1. View Hint View Answer Discuss in Forum

    Distance covered = 200 + 160 = 360.
    Speed of train = 72 km = 72 x (5/18) = 20 sec.

    Correct Option: A

    Distance covered = 200 + 160 = 360.
    Speed of train = 72 km = 72 x (5/18) = 20 sec.
    Time = 360 / 20 = 18 sec.

  1. A train 540 m long is running with a speed of 72 km/hr. In what time it pass a tunnel 160 m long ?








  1. View Hint View Answer Discuss in Forum

    ∵ Speed of the train = 72 km/hr = 72 x (5/18) = 20 m/sec.
    Sum of the length of the train and tunnel = 540 + 160 = 700 metres.

    Correct Option: C

    ∵ Speed of the train = 72 km/hr = 72 x (5/18) = 20 m/sec.
    Sum of the length of the train and tunnel = 540 + 160 = 700 metres.

    ∴ Required time taken to pass the tunnel = Time taken to cover 700 metres at 20 m/sec.
    = 700/20
    = 35 sec.

  1. A column of men, extending 250 metres in length takes one hour to march through a street at the rate of 50 paces a minute, each pace being 75 cm. Find the length of the street ?








  1. View Hint View Answer Discuss in Forum

    Speed of the column of men = (50 x 75) / (100 x 60) = 5/8 m/sec.
    Let the length of the street be L metres
    ∵ (L + 250) = (60 x 60 x 5) / 8

    Correct Option: A

    Speed of the column of men = (50 x 75) / (100 x 60) = 5/8 m/sec.
    Let the length of the street be L metres
    ∵ (L + 250) = (60 x 60 x 5) / 8 = 2250 metres
    ⇒ L = (2250 - 250) m
    ∴ L = 2000 m = 2 km.