LCM and HCF
-  Product of two co-prime numbers is 117. Then their L.C.M. is
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                        View Hint View Answer Discuss in Forum HCF of two-prime numbers = 1 
 As we know that ,
 Product of numbers = LCM × HCF
 ∴ Product of numbers = LCM × 1 = 117
 Their LCM = 117 = 13 × 9 , where 13 & 9 are co-prime.Correct Option: AHCF of two-prime numbers = 1 
 As we know that ,
 Product of numbers = LCM × HCF
 ∴ Product of numbers = LCM × 1 = 117
 Their LCM = 117 = 13 × 9 , where 13 & 9 are co-prime.
 L.C.M ( 13 , 9 ) = 117.
-  The LCM of two numbers is 4 times their HCF. The sum of LCM and HCF is 125. If one of the number is 100, then the other number is
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                        View Hint View Answer Discuss in Forum Let LCM be L and HCF be H, then 
 According to question ,
 L = 4H
 sum of LCM and HCF = 125
 ⇒ H + 4H = 125
 ⇒ 5H = 125⇒ H = 125 = 25 5 
 ∴ L = 4 × 25 = 100
 Correct Option: BLet LCM be L and HCF be H, then 
 According to question ,
 L = 4H
 sum of LCM and HCF = 125
 ⇒ H + 4H = 125
 ⇒ 5H = 125⇒ H = 125 = 25 5 
 ∴ L = 4 × 25 = 100∴ Second number = L × H First number Second number = 100 × 25 = 25 100 
-  The H.C.F. of two numbers is 96 and their L.C.M. is 1296. If one of the number is 864, the other is
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                        View Hint View Answer Discuss in Forum Here , LCM = 1296 , HCF = 96 , First number = 864 , Second number = ? 
 As We know that ,
 First number × Second number = HCF × LCM
 ⇒ 864 × Second number = 96 × 1296Correct Option: DHere , LCM = 1296 , HCF = 96 , First number = 864 , Second number = ? 
 As We know that ,
 First number × Second number = HCF × LCM
 ⇒ 864 × Second number = 96 × 1296⇒ Second number = 96 × 1296 = 144 864 
-  The LCM of two numbers is 520 and their HCF is 4. If one of the number is 52, then the other number is
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                        View Hint View Answer Discuss in Forum Given that , LCM = 520 , HCF = 4 , First number = 52, Second number = ? 
 We can find other number with the help of the given formula ,
 First number × second number = HCF × LCM
 ⇒ 52 × second number = 4 × 520Correct Option: AGiven that , LCM = 520 , HCF = 4 , First number = 52, Second number = ? 
 We can find other number with the help of the given formula ,
 First number × second number = HCF × LCM
 ⇒ 52 × second number = 4 × 520⇒ Second number = 4 × 520 = 40 52 
-  The HCF of two numbers is 15 and their LCM is 225. If one of the number is 75, then the other number is :
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                        View Hint View Answer Discuss in Forum Given , LCM = 225 , HCF = 15 , First number = 75 , Second number = ? 
 As We know that ,
 First number × Second number = HCF × LCM
 ⇒ 75 × Second number = 15 × 225∴ Second number = 15 × 225 75 Correct Option: DGiven , LCM = 225 , HCF = 15 , First number = 75 , Second number = ? 
 As We know that ,
 First number × Second number = HCF × LCM
 ⇒ 75 × Second number = 15 × 225∴ Second number = 15 × 225 = 45 75 
 
	