LCM and HCF
-  The HCF and LCM of two numbers are 18 and 378 respectively. If one of the number is 54, then the other number is
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                        View Hint View Answer Discuss in Forum Given , LCM = 378 , HCF = 18 , First number = 54 , Second number = ? 
 As We know that ,Second number = HCF × LCM First number 
 Correct Option: AGiven , LCM = 378 , HCF = 18 , First number = 54 , Second number = ? 
 As We know that ,Second number = HCF × LCM First number Second number = 18 × 378 = 126 54 
-  The LCM of two numbers is 520 and their HCF is 4. If one of the number is 52, then the other number is
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                        View Hint View Answer Discuss in Forum Given that , LCM = 520 , HCF = 4 , First number = 52, Second number = ? 
 We can find other number with the help of the given formula ,
 First number × second number = HCF × LCM
 ⇒ 52 × second number = 4 × 520Correct Option: AGiven that , LCM = 520 , HCF = 4 , First number = 52, Second number = ? 
 We can find other number with the help of the given formula ,
 First number × second number = HCF × LCM
 ⇒ 52 × second number = 4 × 520⇒ Second number = 4 × 520 = 40 52 
-  The HCF of two numbers is 15 and their LCM is 225. If one of the number is 75, then the other number is :
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                        View Hint View Answer Discuss in Forum Given , LCM = 225 , HCF = 15 , First number = 75 , Second number = ? 
 As We know that ,
 First number × Second number = HCF × LCM
 ⇒ 75 × Second number = 15 × 225∴ Second number = 15 × 225 75 Correct Option: DGiven , LCM = 225 , HCF = 15 , First number = 75 , Second number = ? 
 As We know that ,
 First number × Second number = HCF × LCM
 ⇒ 75 × Second number = 15 × 225∴ Second number = 15 × 225 = 45 75 
-  The HCF and product of two numbers are 15 and 6300 respectively. The number of possible pairs of the numbers is
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                        View Hint View Answer Discuss in Forum Here , HCF = 15 
 Let the number be 15p and 15q, where p and q are co – prime.
 With the help of the given formula ,
 HCF × LCM = Product of two numbers
 ∴ 15p × 15q = 6300⇒ pq = 6300 = 28 15 × 15 
 Correct Option: CHere , HCF = 15 
 Let the number be 15p and 15q, where p and q are co – prime.
 With the help of the given formula ,
 HCF × LCM = Product of two numbers
 ∴ 15p × 15q = 6300⇒ pq = 6300 = 28 15 × 15 
 So, two pairs are ( 7 , 4 ) and ( 14 , 2 ) .
 Hence , required answer is 2.
-  The H.C.F. of two numbers is 96 and their L.C.M. is 1296. If one of the number is 864, the other is
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                        View Hint View Answer Discuss in Forum Here , LCM = 1296 , HCF = 96 , First number = 864 , Second number = ? 
 As We know that ,
 First number × Second number = HCF × LCM
 ⇒ 864 × Second number = 96 × 1296Correct Option: DHere , LCM = 1296 , HCF = 96 , First number = 864 , Second number = ? 
 As We know that ,
 First number × Second number = HCF × LCM
 ⇒ 864 × Second number = 96 × 1296⇒ Second number = 96 × 1296 = 144 864 
 
	