Analog circuits miscellaneous
- The period of the output waveform for the circuit of figure shown, when triggered by a negative pulse is
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T = (1.1) RAC
= 1.1(7.5 × 103) (0.1 × 10– 6) = 0.825 ms.Correct Option: B
T = (1.1) RAC
= 1.1(7.5 × 103) (0.1 × 10– 6) = 0.825 ms.
- The circuit shown in the figure
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NA
Correct Option: A
NA
- For the oscillator circuit shown in the given figure, expression for the time period of oscillation can be given by (where t = RC)
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T = 2RC ln 1 + β 1 - β Here , β = 1 = R 2 R + R
∴ T = 2 RC ln 3 = 2 τ ln 3Correct Option: B
T = 2RC ln 1 + β 1 - β Here , β = 1 = R 2 R + R
∴ T = 2 RC ln 3 = 2 τ ln 3
- A voltage source VAB = 4 sinωt is applied to the terminals A and B of the circuit shown in the given figure. The diodes are assumed to be ideal. The impedance by the circuit across the terminals A and B is _________ kΩ .
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Diode D1 conducts through 10 kΩ on the extreme right and diode D2 is blocked. Diode D2 conducts through 10 kΩ in the middle branch and diode D1 is blocked. Thus source always sees a resistance of 10 kΩ.
Correct Option: A
Diode D1 conducts through 10 kΩ on the extreme right and diode D2 is blocked. Diode D2 conducts through 10 kΩ in the middle branch and diode D1 is blocked. Thus source always sees a resistance of 10 kΩ.
- If α = 0.98, ICO = 6 µA and Iβ = 100 A for a transistor, then value of IC will be _______ mA
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IC = ICO + α IB = 6 + 0.98 × 100 = 5.2 mA 1 - α 1 - α 1 - 0.98 1 - 0.98
Correct Option: B
IC = ICO + α IB = 6 + 0.98 × 100 = 5.2 mA 1 - α 1 - α 1 - 0.98 1 - 0.98