96. In the circuit shown in the figure, if CMRR of the OP-AMP is 60dB, then magnitude of the v₀ is
    
    

1. 1. 1 mV

   
   
   

   2. 2 mV

   
   
   

   3. 100 mV

   
   
   

   4. 200 mV

   
   
   

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1. View Hint View Answer Discuss in Forum

   υ_ = (2)	R	= 1 V , υd = 0
   	2R

   
   

   VCM =	υ+ + υ_	= 1
   	2

   
   

   υ0 =	RF		VCM
   	1		CMRR

   
   Here, CMRR = 60 dB = 10³
   

   ∴ υ0 =	100		1	= 100 mV
   	1		103

   Correct Option: C

   υ_ = (2)	R	= 1 V , υd = 0
   	2R

   
   

   VCM =	υ+ + υ_	= 1
   	2

   
   

   υ0 =	RF		VCM
   	1		CMRR

   
   Here, CMRR = 60 dB = 10³
   

   ∴ υ0 =	100		1	= 100 mV
   	1		103

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97. Out put of the OPAMP shown below will be (assuming it to be ideal)
    
    
    

1. 1. zero
      

   
   
   

   2. – (V₁ – V₂) sin ωt

   
   
   

   3. + (V₁ + V₂) sin ωt
      

   
   
   

   4. – (V₁ + V₂) sin ωt

   
   
   

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1. View Hint View Answer Discuss in Forum

   NA

   Correct Option: D

   NA

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98. A circuit using an OPAMP shown below, has
    
    

1. 1. voltage series feedback
      

   
   
   

   2. voltage shunt feedback
      

   
   
   

   3. current shunt feedback
      

   
   
   

   4. current series feedback

   
   
   

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1. View Hint View Answer Discuss in Forum

   If =	Vi - Vo	≈ -	Vo	= βVo		β = -	1
   	Rf		Rf				Rf

   
   As feedback current is proportional to output voltage, it is a voltage-shunt feedback amplifier.

   Correct Option: B

   If =	Vi - Vo	≈ -	Vo	= βVo		β = -	1
   	Rf		Rf				Rf

   
   As feedback current is proportional to output voltage, it is a voltage-shunt feedback amplifier.

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99. Output voltage of an OP-AMP for input voltage of V_i1 = 150 μV, V_i22 = 140 μV if amplifier has a differential gain of Ad = 4000 and value of CMRR is 100, is
    

1. 1. 45.8 mV

   
   
   

   2. 40.006 mV

   
   
   

   3. 10 μV

   
   
   

   4. 145 μV

   
   
   

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1. View Hint View Answer Discuss in Forum

   V0 = Ad Vd		1 +	1	Vc
   			CMRR	Vd

   
   

   = (400) (10 V)		1 +	1	145 μ V		= 45.8 mV
   			100	10 μ V

   
   

   Correct Option: A

   V0 = Ad Vd		1 +	1	Vc
   			CMRR	Vd

   
   

   = (400) (10 V)		1 +	1	145 μ V		= 45.8 mV
   			100	10 μ V

   
   

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100. For the circuit shown in the given figure, assuming ideal diodes, output waveform V₀ will be
     

1. 1. 
      

   
   
   

   2. 
      

   
   
   

   3. 
      

   
   
   

   4. 
      

   
   
   

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1. View Hint View Answer Discuss in Forum

   Voltage at OP-AMP output
   V₁ = – 1– 5 sin ωt
   

   At ωt =	π	, V0 = -6 volts
   	2

   
   

   At ωt =	3π	, V0 = 4 volts
   	2

   
   During ‘– ’ ve cycl e of t he waveform, when V_I <– 2V, diode D₂ conducts and V₀ = – 2V
   During ‘+’ ve cycle, when V₁ > 2V, D₁ conducts and V₀ = 2V.

   Correct Option: D

   Voltage at OP-AMP output
   V₁ = – 1– 5 sin ωt
   

   At ωt =	π	, V0 = -6 volts
   	2

   
   

   At ωt =	3π	, V0 = 4 volts
   	2

   
   During ‘– ’ ve cycl e of t he waveform, when V_I <– 2V, diode D₂ conducts and V₀ = – 2V
   During ‘+’ ve cycle, when V₁ > 2V, D₁ conducts and V₀ = 2V.

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