Analog circuits miscellaneous
- If differential amplifier has a differential gain of 20,000. CMRR = 80 dB, then common mode gain is
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20 log Ad = 80 Ac ⇒ Ad = 104 Ac ⇒ Ad = Ac 104 ⇒ Ac = 2 × 104 = 2 104
Correct Option: A
20 log Ad = 80 Ac ⇒ Ad = 104 Ac ⇒ Ad = Ac 104 ⇒ Ac = 2 × 104 = 2 104
- In the OP-AMP circuit shown in the given figurs V0 is given by
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V0 = 3R = 3 Vs R
⇒ V0 = 3VsCorrect Option: C
V0 = 3R = 3 Vs R
⇒ V0 = 3Vs
- OPAMP used as a tuned amplifier has the tuned circuit connected
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NA
Correct Option: C
NA
- For the circuit shown in the given figure, assuming ideal diodes, output waveform V0 will be
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Voltage at OP-AMP output
V1 = – 1– 5 sin ωtAt ωt = π , V0 = -6 volts 2 At ωt = 3π , V0 = 4 volts 2
During ‘– ’ ve cycl e of t he waveform, when VI <– 2V, diode D2 conducts and V0 = – 2V
During ‘+’ ve cycle, when V1 > 2V, D1 conducts and V0 = 2V.Correct Option: D
Voltage at OP-AMP output
V1 = – 1– 5 sin ωtAt ωt = π , V0 = -6 volts 2 At ωt = 3π , V0 = 4 volts 2
During ‘– ’ ve cycl e of t he waveform, when VI <– 2V, diode D2 conducts and V0 = – 2V
During ‘+’ ve cycle, when V1 > 2V, D1 conducts and V0 = 2V.
- Out put of the OPAMP shown below will be (assuming it to be ideal)
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NA
Correct Option: D
NA