Industrial Engineering Miscellaneous
- If at the optimum in a linear programming problem, a dual variable corresponding to a particular primal constraint is zero, then it means that
-
View Hint View Answer Discuss in Forum
NA
Correct Option: C
NA
- In an assembly line for assembling toys, five workers are assigned tasks which take times of 10, 8, 6, 9 and 10 minutes respectively. The balance delay for line is
-
View Hint View Answer Discuss in Forum
Assuming cycle time = 10 + 8 + 6 + 9 + 10 = 43
Balance delay = 1 - ∑ ti = 1- 43 = 0.14 n × te 5 × 10
= 14%Correct Option: C
Assuming cycle time = 10 + 8 + 6 + 9 + 10 = 43
Balance delay = 1 - ∑ ti = 1- 43 = 0.14 n × te 5 × 10
= 14%
- If the demand for an item is doubled and the ordering cost halved, the economic order quantity
-
View Hint View Answer Discuss in Forum
EOQ ∝ √DC0
EOQ' = EOQ √D'C0' √DC0
D' = 2DC0' = 1 C0 2 ∴ EOQ' = EOQ √{ 2D × ( C0 / 2 ) } √DC0
⇒ EOQ' = EOQCorrect Option: A
EOQ ∝ √DC0
EOQ' = EOQ √D'C0' √DC0
D' = 2DC0' = 1 C0 2 ∴ EOQ' = EOQ √{ 2D × ( C0 / 2 ) } √DC0
⇒ EOQ' = EOQ
- When the annual demand of a product is 24000 units, the EOQ (Economic Order Quantity) is 2000 units. If the annual demand is 48000 units the most appropriate EOQ will be
-
View Hint View Answer Discuss in Forum
EOQ ∝ √D
EOQ2 = EOQ1 √D2 √D1 EOQ2 = EOQ1 × √D2 √D1 EOQ2 = 2000 × √4800 = 2828 √2400
Correct Option: C
EOQ ∝ √D
EOQ2 = EOQ1 √D2 √D1 EOQ2 = EOQ1 × √D2 √D1 EOQ2 = 2000 × √4800 = 2828 √2400
- In an ideal inventory control system, the economic lot size for a part is 1000. If the annual demand for the part is doubled, the new economic lot size required will be
-
View Hint View Answer Discuss in Forum
EOQ ∝ √D
EOQ = 1000EOQ1 = EOQ √D √D EOQ1 = 1000 × √2D = 1000√2 √D Correct Option: D
EOQ ∝ √D
EOQ = 1000EOQ1 = EOQ √D √D EOQ1 = 1000 × √2D = 1000√2 √D