Industrial Engineering Miscellaneous
- The number of customers arriving at a railway reservation counter is Poisson distributed with an arrival rate of eight customers per hour. The reservation clerk at this counter takes six minutes per customer on an average with an exponentially distributed service time. The average number of the customers in the queue will be
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Average number of customer in queue
= λ2 = 8 × 8 = 3.2 μ(μ − A) 10 × (10 − 8) Correct Option: B
Average number of customer in queue
= λ2 = 8 × 8 = 3.2 μ(μ − A) 10 × (10 − 8)
- Consider a single server queuing model with Poisson arrivals (λ = 4/hour) and exponential service (λ = 4/hour). The number in the system is restricted to a maximum of 10. The probability that a person who comes in leaves without joining the queue is
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When
ρ = 1,pn = 1 N + 1 Correct Option: A
When
ρ = 1,pn = 1 N + 1
- A maintenance service facility has Poisson arrival rates, negative exponential service time and operates on a 'first come first served' queue discipline. Break-downs occur on an average of 3 per day with a range of zero to eight. The maintenance crew can service an average of 6 machines per day with a range of zero to seven. The mean waiting time for an item to be serviced would be
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Given: λ = 3 per day (arrival rate)
μ = 6 per day (service rate)
Mean waiting time for an item to serviced= λ = 3 = 1 × 1 = 1 day. μ(μ − λ) 6(6 − 3) 2 3 6 Correct Option: A
Given: λ = 3 per day (arrival rate)
μ = 6 per day (service rate)
Mean waiting time for an item to serviced= λ = 3 = 1 × 1 = 1 day. μ(μ − λ) 6(6 − 3) 2 3 6
- An electronic equipment manufacturer has decided to add a component subassembly operation that can produce 80 units during a regular 8-hour shift. This operation consists of three activities as below
For line balancing the number of work stations required for the activities M, E and T would respectively be
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Number of units produce in a day = so units working hour in a day = 8 hours
Time taken to produce 1 unit = 8 × 60 = 6 min 80
T = 6 min
Number of work station are the whole number more the function.
So no of work station required for the activities, M, E & T would be 2, 3, 4, 1Correct Option: A
Number of units produce in a day = so units working hour in a day = 8 hours
Time taken to produce 1 unit = 8 × 60 = 6 min 80
T = 6 min
Number of work station are the whole number more the function.
So no of work station required for the activities, M, E & T would be 2, 3, 4, 1
- A soldering operation was work-sampled over two days (16 hours) during which an employee soldered 108 joints, actual working time was 90% of the total time and the performance rating was estimated to be 120 percent. If the contract provides allowance of 20 percent of the total time available, the standard time for the operation would be
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Total time = 16 hours
T = 16 × 60 = 960 minActual time = 90 × 960 = 864 minute 100
Normal time T normal = 120% of 864⇒ 120 × 864 = 1036.8 min 100
Total Standard time: TstandardTstandard = Tnormal 1 − 20 100 = 1036.8 = 1036.8 = 1296 min 1 − 0.2 0.8
No. of Joints soldered(N)
N = 108.
Standard time for operation⇒ 1296 = 12min 108 Correct Option: D
Total time = 16 hours
T = 16 × 60 = 960 minActual time = 90 × 960 = 864 minute 100
Normal time T normal = 120% of 864⇒ 120 × 864 = 1036.8 min 100
Total Standard time: TstandardTstandard = Tnormal 1 − 20 100 = 1036.8 = 1036.8 = 1296 min 1 − 0.2 0.8
No. of Joints soldered(N)
N = 108.
Standard time for operation⇒ 1296 = 12min 108
