Speed, Time and Distance


  1. A train 200 m long running at 36 kmph takes 55 seconds to cross a bridge. The length of the bridge is









  1. View Hint View Answer Discuss in Forum

    Speed of train = 36kmph

    = 36 ×
    5
    = 10 m/sec.
    18

    If the length of bridge be x metre, then
    10 =
    200 + x
    55

    ⇒  200 + x = 550
    ⇒  x = 550 – 200 = 350 metre.

    Second Method :
    Here, x = 200 m
    u = 36 km/hr,
    36 × 5
    m/second = 10 m/sec
    18

    y = ?, t = 55 sec
    using
    t =
    x + y
    u

    55 =
    200 + y
    10

    y = 550 – 200
    y = 350 m

    Correct Option: C

    Speed of train = 36kmph

    = 36 ×
    5
    = 10 m/sec.
    18

    If the length of bridge be x metre, then
    10 =
    200 + x
    55

    ⇒  200 + x = 550
    ⇒  x = 550 – 200 = 350 metre.

    Second Method :
    Here, x = 200 m
    u = 36 km/hr,
    36 × 5
    m/second = 10 m/sec
    18

    y = ?, t = 55 sec
    using
    t =
    x + y
    u

    55 =
    200 + y
    10

    y = 550 – 200
    y = 350 m


  1. A man covers a total distance of 100 km on bicycle. For the first 2 hours, the speed was 20 km/hr and for the rest of the journey, it came down to 10 km/hr. The average speed will be









  1. View Hint View Answer Discuss in Forum

    Distance covered in first 2 hours
    = 2 × 20 = 40 km.
    Remaining distance
    = 100 – 40 = 60 km.
    Time taken in covering 60 km at 10 kmph

    =
    60
    = 6 hours
    10

    ∴  Required average speed =
    Total distance
    Total Time

    =
    100
    kmph
    2 + 6

    =
    100
    kmph
    8

    =
    25
    kmph
    2

    = 12
    1
    kmph
    2

    Correct Option: A

    Distance covered in first 2 hours
    = 2 × 20 = 40 km.
    Remaining distance
    = 100 – 40 = 60 km.
    Time taken in covering 60 km at 10 kmph

    =
    60
    = 6 hours
    10

    ∴  Required average speed =
    Total distance
    Total Time

    =
    100
    kmph
    2 + 6

    =
    100
    kmph
    8

    =
    25
    kmph
    2

    = 12
    1
    kmph
    2



  1. On a journey across Kolkata, a taxi averages 50 km per hour for 50% of the distance, 40 km per hour for 40% of it and 20 km per hour for the remaining. The average speed (in km/hour) for the whole journey is :









  1. View Hint View Answer Discuss in Forum

    Total distance = 100 km.

    Total time =
    50
    +
    40
    +
    10
    504020

    = 1 + 1 +
    1
    =
    5
    hours
    22

    ∴ Average speed =
    100 × 2
    = 40 kmph
    5

    Correct Option: B

    Total distance = 100 km.

    Total time =
    50
    +
    40
    +
    10
    504020

    = 1 + 1 +
    1
    =
    5
    hours
    22

    ∴ Average speed =
    100 × 2
    = 40 kmph
    5


  1. A train goes from Ballygunge to Sealdah at an average speed of 20 km/hour and comes back at an average speed of 30 km/hour. The average speed of the train for the whole journey is









  1. View Hint View Answer Discuss in Forum

    Required average speed =
    2 × 30 × 20
    30 + 20

    [∵  Distance covered is same]
    =
    2 × 30 × 20
    = 24 kmph
    50

    Correct Option: D

    Required average speed =
    2 × 30 × 20
    30 + 20

    [∵  Distance covered is same]
    =
    2 × 30 × 20
    = 24 kmph
    50



  1. A and B are 20 km apart. A can walk at an average speed of 4 km/hour and B at 6 km/hr. If they start walking towards each other at 7 a.m., when they will meet ?









  1. View Hint View Answer Discuss in Forum

    If A and B meet after t hours, then
    4 t + 6 t = 20
    ⇒  10 t = 20

    ⇒  t =
    20
    = 2 hours.
    10

    Hence, both will meet at 9 a.m.

    Correct Option: C

    If A and B meet after t hours, then
    4 t + 6 t = 20
    ⇒  10 t = 20

    ⇒  t =
    20
    = 2 hours.
    10

    Hence, both will meet at 9 a.m.