Speed, Time and Distance
- If speed of 31/3 m/s is converted to km/h, then it would be
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∵ 1 m/s = 18/5 km/h
Correct Option: D
∵ 1 m/s = 18/5 km/h
∴ 31/3 m/s = 10/3 m/s = (10/3) x (18/5) km/h
= 12 km/h
- If a person travel 39 km at a speed of 26 km/h, another 39 km at a speed of 39 km/h and 39 km again at a speed of 52 km/h . Then find the average speed of entire journey
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Average speed of entire journey
= (39 + 39 + 39)/(39/26 + 39/39 +39/52)Correct Option: C
Average speed of entire journey
= (39 + 39 + 39)/(39/26 + 39/39 +39/52)
= 3/(1/26 + 1/39 +1/52)
= 3/[(6 + 4 + 3)/156]
= 3 x 156/13 = 36 km/h
- A and B are 20 km apart. A can walk at an average speed of 4 km/hr and B at 6 km/h. If they start walking towards each other at 7:000 am, when they will meet?
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Sum of distance traveled by them after T hours
6T + 4T = 20 KM
T = 2 hours.Correct Option: C
Suppose they will meet after T hours.
Distance = Speed x Time
Sum of distance traveled by them after T hours
6T + 4T = 20 km
T = 2 hours.
So they will meet at 7:00 AM + 2 hours = 9:00 AM
- A boat moves downstream at 1 km in 5 minutes and upstream at 1 km in 12 minutes.What is the speed of current?
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Sd = 12 km/h
Su = 5 km/h
Speed of current = (Sd - Su)/2Correct Option: B
Sd = 12 km/h
Su = 5 km/h
Speed of current = (12 - 5)/2 = 3.5 km/h
- A man takes 4 h 20 min in walking to a certain place and riding back. If he walk on both sides he losses 1 h. The time he would take by riding both ways is ?
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W + R = 4 h 20 min
W + W = 5 h 20 minCorrect Option: B
W + R = 4 h 20 min
W + W = 5 h 20 min
∴ R + R = 3 h 20 min