Speed, Time and Distance
- A is twice as fast as B and B is thrice as fast as C is. The journey
covered by C in 1 1 hours will be covered by A in 2
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Speed of B = x kmph (let)
Speed of A = 2x kmphSpeed of C = x kmph 3 ∴ Speed of A = 2x = 6 Speed of C (x/3) ∴ Required time = 1 of 3 hours 6 2 = 1 hour = 15 minutes 4 Correct Option: A
Speed of B = x kmph (let)
Speed of A = 2x kmphSpeed of C = x kmph 3 ∴ Speed of A = 2x = 6 Speed of C (x/3) ∴ Required time = 1 of 3 hours 6 2 = 1 hour = 15 minutes 4
- A truck travels at 90 km/hr for
Find the time taken by the truck to travel 310 kilometres.the first 1 1 hours. After that it travels at 70 km/hr. 2
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Distance covered by truck in 3 hours 2
= Speed × Time= 90 × 3 = 135 km 2
Remaining distance
= 310 – 135 = 175 km
∴ Time taken at 70 kmph= 175 = 2.5 hours 70
∴ Total time = 1.5 + 2.5 = 4 hoursCorrect Option: D
Distance covered by truck in 3 hours 2
= Speed × Time= 90 × 3 = 135 km 2
Remaining distance
= 310 – 135 = 175 km
∴ Time taken at 70 kmph= 175 = 2.5 hours 70
∴ Total time = 1.5 + 2.5 = 4 hours
- The lengths of a train and that of a platform are equal. If with a speed of 90 km/hr the train
crosses the platform in one minute, then the length of the train (in metres) is
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Let, length of train = length of platform = x metre
Speed of train = 90 kmph= 90 × 5 m/sec. 18
= 25 m/sec.∴ Speed of train = Length of platform and train Time taken in crossing ⇒ 25 = 2x ⇒ 2x = 25 × 60 60 ⇒ x = 25 × 60 = 750 metre 2 Correct Option: C
Let, length of train = length of platform = x metre
Speed of train = 90 kmph= 90 × 5 m/sec. 18
= 25 m/sec.∴ Speed of train = Length of platform and train Time taken in crossing ⇒ 25 = 2x ⇒ 2x = 25 × 60 60 ⇒ x = 25 × 60 = 750 metre 2
- A train 50 metres long passes a platform of length 100 metres in 10 seconds. The speed of the train in metre/second is
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Speed of train = Length of (train + platform) Time taken to crossing = (50 + 100) 10 = 150 = 15 m/sec 10 Correct Option: C
Speed of train = Length of (train + platform) Time taken to crossing = (50 + 100) 10 = 150 = 15 m/sec 10
- A train 50 metre long passes a platform 100 metre long in 10 seconds. The speed of the train in km/hr is
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Speed of train = Length of platform and train Time taken to crossing = 100 + 50 metre/second 10
= 15 metre/second= 15 × 18 kmph 5
= 54 kmphCorrect Option: B
Speed of train = Length of platform and train Time taken to crossing = 100 + 50 metre/second 10
= 15 metre/second= 15 × 18 kmph 5
= 54 kmph