Speed, Time and Distance
- A train is moving with a speed of 92.4 km/hr. how many meters will it cover in 10 min. ?
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Speed in m/sec = ( 5 / 18 ) x Speed in kms/hr.
92.4 kms/hr = 92.4 x (5 / 18) m/sec.
∴ Req. distance = 92.4 x ( 5 / 18 ) x 600 metersCorrect Option: B
Speed in m/sec = ( 5 / 18 ) x Speed in kms/hr.
92.4 kms/hr = 92.4 x (5 / 18) m/sec.
∴ Req. distance = 92.4 x ( 5 / 18 ) x 600 meters
= 15400 m.
- If a man takes 4 hours to cover a distance of 15 km. how much time will be needed to cover 63 km. at the same speed ?
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Required time = (4 / 15) x 63 hrs.
Correct Option: B
Required time = (4 / 15) x 63 hrs.
= 16 hrs. 48 min
- A distance is covered in 2 hours 45 min at 4 km/hr How much time will be taken to cover it at 16.5 km/hr ?
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Distance = (4 x 11/4 )km.
= 11 km.
∴ Req. Time = 11km / (33/2) km/hrCorrect Option: A
Distance = (4 x 11/4 )km.
= 11 km.
∴ Req. Time = 11km / (33/2) km/hr
= 2 x (11 / 33) hr.
=(2 / 3) x 60 minutes
= 40 minutes
- A boy goes to school with a speed of 3 km/hr. and return to the village with a speed of 2 km/hr. If he takes 5 hours in all, then distance between the village and the school is ?
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Let The required distance be y km.
Then, y/3 + y/2 = 5Correct Option: A
Let The required distance be y km.
Then, y/3 + y/2 = 5
⇒ 2y + 3y = 30
⇒ y = 6 km
- Shard cover two-third of a certain distance at 4 km/hr and the remaining at 5 km/hr. If he takes 42 minutes in all, the distance is ?
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Let total distance be y km.
Then , (2y / 3) / 4 + ( y / 3) / 5 = 42/60Correct Option: D
Let total distance be y km.
Then , (2y / 3) / 4 + ( y / 3) / 5 = 42/60
⇒ y/6 + y/ 15 = 7/10
⇒ 5y + 2y = 21
∴ y = 3
∴ Required distance = 3 km.