Simplification


  1. The digit at unit’s place of the number (1570)2 + (1571)2 + (1572)2 + (1573)2 is :









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    Unit’s digit in (1570)2 = 0
    Unit’s digit in (1571)2 = 1
    Unit’s digit in (1572)2 = 4
    Unit’s digit in (1573)2 = 9
    ∴  Required unit’s digit
    = Unit’s digit in (0 +1 + 4 + 9) = 4

    Correct Option: A

    Unit’s digit in (1570)2 = 0
    Unit’s digit in (1571)2 = 1
    Unit’s digit in (1572)2 = 4
    Unit’s digit in (1573)2 = 9
    ∴  Required unit’s digit
    = Unit’s digit in (0 +1 + 4 + 9) = 4


  1. The digit at the unit’s place in the square-root of 15876 is :









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    15876 = 126
    The digit at the unit’s place is 6.

    Correct Option: B

    15876 = 126
    The digit at the unit’s place is 6.



  1. The fourth root of 24010000 is









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    24010000 = 4900
    Again,   √4900 = 70
    ∴  424010000 = 70

    Correct Option: D

    24010000 = 4900
    Again,   √4900 = 70
    ∴  424010000 = 70


  1. Find the value of √156.25 + √0.0081 − √0.0361









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    Expression
    = √156.25 + √0.0081 − √0.0361
    = 12.5 + 0.09 – 0.19 = 12.4

    Correct Option: C

    Expression
    = √156.25 + √0.0081 − √0.0361
    = 12.5 + 0.09 – 0.19 = 12.4



  1. The square root of 33 – 4√35 is :









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    33 – 4√35
    = 33 – 2 × 2√5 × 7
    = 33 – 2 × 2√7 × √5
    = 28 + 5 – 2 × 2 √7 × √5
    = (2√7)2 + (√5)2 – 2 × 2 √7 × √5
    = (2√7 − √5)2
    ∴  √33 − 4√35
    = √(2√7 − √5)2
    = ±(2√7 − √5)

    Correct Option: D

    33 – 4√35
    = 33 – 2 × 2√5 × 7
    = 33 – 2 × 2√7 × √5
    = 28 + 5 – 2 × 2 √7 × √5
    = (2√7)2 + (√5)2 – 2 × 2 √7 × √5
    = (2√7 − √5)2
    ∴  √33 − 4√35
    = √(2√7 − √5)2
    = ±(2√7 − √5)