Simplification
- The number of pairs of natural numbers, the difference of whose squares is 45 will be
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Let the numbers be x and y where x > y
∴ x2 − y2 = 45
⇒ (x + y)(x – y) = 45
Now, 45 = 5 × 9
= 15 × 3 = 45 × 1
∴ Number of pairs = 3Correct Option: B
Let the numbers be x and y where x > y
∴ x2 − y2 = 45
⇒ (x + y)(x – y) = 45
Now, 45 = 5 × 9
= 15 × 3 = 45 × 1
∴ Number of pairs = 3
- The value of √19.36 + √0.1936 + √0.001936 + √0.00001936 is :
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√19.36 + √0.1936 + √0.001936 + √0.00001936
= 4.4 + 0.44 + 0.044 + 0.0044
= 4.8884Correct Option: C
√19.36 + √0.1936 + √0.001936 + √0.00001936
= 4.4 + 0.44 + 0.044 + 0.0044
= 4.8884
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The value of √ 0.064 × 0.256 × 15.625 is 0.25 × 0.625 × 4.096
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Expression
= √ 0.064 × 0.256 × 15.625 0.025 × 0.625 × 4.096 = √ 64 × 256 × 15625 25 × 625 × 4096 = 8 × 16 × 25 = 2 5 × 25 × 64 Correct Option: A
Expression
= √ 0.064 × 0.256 × 15.625 0.025 × 0.625 × 4.096 = √ 64 × 256 × 15625 25 × 625 × 4096 = 8 × 16 × 25 = 2 5 × 25 × 64
- If (1101)2 = 1212201, find the value of √121.220l .
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(1101)2 = 1212201
⇒ 1101 = √1212201
√121.2201⇒ √ 121.2201 = 1101 = 11.01 10000 100 Correct Option: B
(1101)2 = 1212201
⇒ 1101 = √1212201
√121.2201⇒ √ 121.2201 = 1101 = 11.01 10000 100
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The square root of 21 51 is 169
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= 21 51 = 21 × 169 + 51 = 3600 169 169 169 ∴ √ 21 51 = √ 3600 = 60 169 169 13 = 4 8 13 Correct Option: B
= 21 51 = 21 × 169 + 51 = 3600 169 169 169 ∴ √ 21 51 = √ 3600 = 60 169 169 13 = 4 8 13