33 – 4√35= 33 – 2 × 2√5 × 7= 33 – 2 × 2√7 × √5= 28 + 5 – 2 × 2 √7 × √5= (2√7)2 + (√5)2 – 2 × 2 √7 × √5= (2√7 − √5)2∴ √33 − 4√35= √(2√7 − √5)2= ±(2√7 − √5)
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