Profit and Loss
- If the cost price of 20 articles is equal to the selling price of 15 articles, find the profit per cent.
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Given that, a = 20 and b = 15
According to the formula,
Profit %= [(a - b) / b] x 100 %Correct Option: B
Given that, a = 20 and b = 15
According to the formula,
Profit %= [(a - b) / b] x 100 %
= (5/15) x 100% = 100/3 %
= 331/3%
- A furniture seller sells two tables ₹ 1500 each. He earned a profit of 20% on one table and suffered a loss of 20% on the another table. Net profit or loss in this deal is
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Required loss = (a/10)2 %
Correct Option: A
Required loss = (a/10)2%
= (20/10)2% = 4%
Thus, seller gets 4% loss in the deal.
- If an article is sold at a gain of 6% instead of at loss of 6%, then the seller gets ₹ 6 more. The cost price of the article is
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Let CP of the article be ₹ N,
Then 106% of N - 94% of N = 6Correct Option: B
Let CP of the article be ₹ N,
Then 106% of N - 94% of N = 6
⇒ 12% of N = 6
∴ N = (6 x 100)/12 = ₹ 50
- A man sold two houses for ₹ 96000 each. In the sale of the first house, he incurred 20% profit and in the sale of the second, he incurred 20% loss. what is the gain or loss percentage in total ?
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Here, a = 20%
∴ Total loss percentage = a2/100 %Correct Option: D
Here, a = 20%
∴ Total loss percentage = a2/100 %
= (20 x 20)/100
= 4%
- A sold a watch to B at 40% gain and B sold it to C at a loss of 20%. if C bought the watch for ₹ 432, at what price did A purchase it ?
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Let A purchased the watch for ₹ N
A x [(1+ r1) /100] x [(1+ r2) /100] = CP of article given by CCorrect Option: A
Let A purchased the watch for ₹ N
A x [(1+ r1) /100] x [(1+ r2) /100] = CP of article given by C
⇒ N x (140/100) x (80/100) = 432
∴ N = (432 x 100)/(14 x 8) = ₹ 385.71