Profit and Loss
- A man buys two hens for Rs. 500 each. He sod one for 15% profit and other for 5% loss. Find his profit percentage ?
-
View Hint View Answer Discuss in Forum
SP. of first hen = (115/100) x 500 = Rs. 575
SP of second hen = (95/100) x 500 = Rs. 475
Total SP = 575 + 475 = Rs. 1050
Total CP = 2 x 500 = Rs. 1000
Gain = SP - CP = (1050 - 1000) = Rs. 50Correct Option: A
SP. of first hen = (115/100) x 500 = Rs. 575
SP of second hen = (95/100) x 500 = Rs. 475
Total SP = 575 + 475 = Rs. 1050
Total CP = 2 x 500 = Rs. 1000
Gain = SP - CP = (1050 - 1000) = Rs. 50
Gain percentage = (50/1000) x 100 = 5%
- A person purchases 100 pens at a discount of 10% . The net amount of money spent by the person to purchase the pens is ₹ 600. The selling expenses incurred by the person are 15% on the net cost price. What should be the selling price for 100 pens in order to earn a profit of 25% ?
-
View Hint View Answer Discuss in Forum
Total cost price = 600 + 15% of 600
= 600 + (600 x 15)/100 = ₹690
Profit = 25%
SP = CP(100 + Profit/100)Correct Option: C
Total cost price = 600 + 15% of 600
= 600 + (600 x 15)/100 = ₹690
Profit = 25%
SP = CP(100 + Profit/100)
= 690{(100 + 25)/100} = (690 x 125) / 100
= ₹ 862.50
- If 7 kg of tea of price ₹ 72 per kg is blended with 33 kg of tea of ₹ 87 per kg and 35 kg of ₹ 85 per kg and the mixture is sold at 15% profit, then what is the selling price of the mixture ?
-
View Hint View Answer Discuss in Forum
CP per kg of the mixture = (w1x1 + w2x2 + w3x3) / (w1 + w2 + w3)
= (7 x 72 + 33 x 87 + 35 x 85)/75
= (504 + 2871 + 2975)/75 = 6350/75 = ₹ 84.66Correct Option: D
CP per kg of the mixture = (w1x1 + w2x2 + w3x3) / (w1 + w2 + w3)
= (7 x 72 + 33 x 87 + 35 x 85)/75
= (504 + 2871 + 2975)/75 = 6350/75 = ₹ 84.66
Profit = 15%
∴ SP per kg = ₹ 84.66 + 15% of ₹ 84.66
= ₹ 97.37
- A person bought two articles for ₹ 1500 and ₹ 1000 respectively one he sold at a gain of 20%. At what price should he sell the other to get a profit of 16% on the whole transaction ?
-
View Hint View Answer Discuss in Forum
CP of first article is ₹ 1500, Gain=20%
SP of first article = (120/100) x 1500 = ₹ 1800
Total CP = 1500 + 1000 = ₹ 2500
Total gain = 16%
Total SP = (116/100) x 2500 = ₹ 2900Correct Option: A
CP of first article is ₹ 1500, Gain=20%
SP of first article = (120/100) x 1500 = ₹ 1800
Total CP = 1500 + 1000 = ₹ 2500
Total gain = 16%
Total SP = (116/100) x 2500 = ₹ 2900
SP of second article = (2900 - 1800) = ₹ 1100
Thus, he should sell the second article at ₹ 1100.
- A manufacturer of a certain item can sell all he can produce at the selling price of ₹ 60 each. It costs him ₹ 40 in materials and labour to produce each item and he has overhead expanses of ₹ 3000 per week in order to operate that plant. The number of units he should produce and sell in order to make a profit of atleast ₹ 1000 per week, is ?
-
View Hint View Answer Discuss in Forum
Suppose the manufacturer should product produce x items.
∴ 60x - (40x + 3000) = 1000
Correct Option: D
Suppose the manufacturer should product produce x items.
∴ 60x - (40x + 3000) = 1000
⇒ 20x = 4000
⇒ x = 200