let SP = N, then CP = 2N/3
Gain = (N - 2N/3) = N/3
&ther4; Gain % = [(N/3) / (2N/3)] x 100%

Correct Option: B

let SP = N, then CP = 2N/3
Gain = (N - 2N/3) = N/3
&ther4; Gain % = [(N/3) / (2N/3)] x 100%
= (N/3) x (3/2N) x 100% = 50%

CP of 6 toffees = ₹ 1,
SP of 6 toffees = 150% of 1 = 150/100 = 3/2

Correct Option: C

CP of 6 toffees = ₹ 1,
SP of 6 toffees = 150% of 1 = 150/100 = 3/2
∵ For ₹ 3/2, the number of toffees sold = 6
∴ For ₹ 1, the number of toffees sold = 6 x (2/3) = 4

Let CP = 5N and SP = 3N
Loss = (CP- SP) = (5N - 3N) = 2N

Correct Option: A

Let CP = 5N and SP = 3N
Loss = (CP- SP) = (5N - 3N) = 2N
Loss % = (2N / 5N) x 100 %
= 40%

SP of 20 eggs = ₹ 1 and gain = 30%
CP of 20 eggs = (1 x 100)/130 = ₹ 10/13
Now, ₹ 10/13 yields 20 eggs.

Correct Option: D

SP of 20 eggs = ₹ 1 and gain = 30%
CP of 20 eggs = (1 x 100)/130 = ₹ 10/13
Now, ₹ 10/13 yields 20 eggs.
∴ ₹ 1 will yield (20 x 13)/10 = 26 eggs
Clearly, 26 eggs were bought for ₹ 1.

Let cost price of article is CP.
According to the formula,
CP = [SP/(100 - Loss %)] x 100

Correct Option: C

Let cost price of article is CP.
According to the formula,
CP = [SP/(100 - Loss %)] x 100
CP = [(100 x 9549)/(100 - 55)]
= ₹ 21220