Profit and Loss


  1. If the cost of price of 16 pens is equal to the selling price of 12 pens, then the gain or loss per cent is









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    Here, a = 16, b = 12
    According to the formula,
    Required gain percent = [(a - b)/b] x 100

    Correct Option: A

    Here, a = 16, b = 12
    According to the formula,
    Required gain percent = [(a - b)/b] x 100
    = [(16 - 12)/12] x 100
    = (4/12) x 100
    = 331/3% (gain)


  1. By selling 100 pens, a shopkeeper gains the selling price of 40 pens. Find his gain percent.











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    (SP of 100 pens) - (CP of 100 pens) = SP of 40 pens
    ⇒ SP of 60 pens = CP of 100 pens.

    Correct Option: E

    (SP of 100 pens) - (CP of 100 pens) = SP of 40 pens
    ⇒ SP of 60 pens = CP of 100 pens.

    Let CP of each pen = ₹ 1
    Then, CP of 60 pens = ₹ 60
    SP of 60 pens = ₹ 100

    Gain = 100 - 60 = ₹ 40
    ∴ Gain % = (40/60) x 100 % = 66.67%



  1. A producer of a tea blends two varieties of tea from tea gardens one costing ₹ 18 per kg and another ₹ 20 kg in the ratio 5 : 3. If he sells the blended variety at ₹ 21 per kg, then his gain percentage is









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    Let quantities of two types of tea costing ₹ 18 per kg and ₹ 20 per kg be 5W kg and 3W kg. respectively.

    Then, CP of tea = (18 x 5W) + (20 x 3W)
    = 90W + 60W = 150W
    SP of tea = 21 x 8W = 168W

    Correct Option: D

    Let quantities of two types of tea costing ₹ 18 per kg and ₹ 20 per kg be 5W kg and 3W kg. respectively.

    Then, CP of tea = (18 x 5W) + (20 x 3W)
    = 90W + 60W = 150W
    SP of tea = 21 x 8W = 168W

    Profit percent = [(168W - 150W) / 150W] x 100%
    = (18/150) x 100% = 12%


  1. By selling 32 orange for ₹ 30 a man loses 25%. How many oranges should be sold for ₹ 24 so as to gain 20% in the transaction ?











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    Let the cost price be ₹ N.
    SP of 1 orange = ₹ 30/32 = ₹ 15/16

    According to the question, 75N/100 = 15/16
    ∴ N = [(15 x 100)/75] x 16 = ₹ 5/4

    SP of 1 orange with 20% profit = ₹ [(5/4) x 120]/100 = ₹ 3/2

    Correct Option: B

    Let the cost price be ₹ N.
    SP of 1 orange = ₹ 30/32 = ₹ 15/16

    According to the question, 75N/100 = 15/16
    ∴ N = [(15 x 100)/75] x 16 = ₹ 5/4

    SP of 1 orange with 20% profit = ₹ [(5/4) x 120]/100 = ₹ 3/2
    ∴ In ₹ 3/2, the number of oranges sold = 1
    ∴ in ₹ 24, the number of oranges sold = (2/3) x 24 = 16



  1. Kamlesh purchased 120 reams of paper at ₹ 100 per ream and the expenditure on transport was ₹ 480. He had to pay an octroi duty of 50 paise per ream and the coolie charges were ₹ 60. What should he charge per ream to gain 40% ?











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    Total cost price = ₹ (120 x 100) = ₹ 12000
    Total expenditure = 480 + (1/2) x 120 + 60 = ₹ 600
    Total cost price = 12000 + 600 = ₹ 126000
    Gain = 40%
    SP of 120 reams = 12600 x (140/100)

    Correct Option: B

    Total cost price = ₹ (120 x 100) = ₹ 12000
    Total expenditure = 480 + (1/2) x 120 + 60 = ₹ 600
    Total cost price = 12000 + 600 = ₹ 126000
    Gain = 40%
    SP of 120 reams = 12600 x (140/100) = ₹ 17640
    ∴ SP per ream = 17640/120 = ₹ 147