Percentage
- Aryan got 350 marks and Vidya scored 76% marks in the same test. If Vidaya scored 296 marks more than Aryan, then what were the maximum marks of the test ?
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Let maximum marks of the exam is N.
According to the question,
Marks obtained by Vidaya = Marks obtained by Aryan + 296
⇒ N x (76/100) = 350 + 296Correct Option: C
Let maximum marks of the exam is N.
According to the question,
Marks obtained by Vidaya = Marks obtained by Aryan + 296
⇒ N x (76/100) = 350 + 296
⇒ N x (76/100) = 646
⇒ N = (646 x 100)/7
⇒ N = 8.5 x 100 = 850
∴ N = 850
- Last year, there were 610 boys in a school. The number decreased by 20% this year. How many girl are there in the school, if the number of boys in the school this year ?
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Last year number of boys in school = 610
∴ Number of boys in school this year = 610 - (610 x 20)/100
= 610 - 122 = 488
∴ Number of girls in school this year
= Number of boys in school this year x 175%
= (488 x 175)/100Correct Option: A
Last year number of boys in school = 610
∴ Number of boys in school this year = 610 - (610 x 20)/100
= 610 - 122 = 488
∴ Number of girls in school this year
= Number of boys in school this year x 175%
= (488 x 175)/100
= (488 x 7)/4
= 122 x 7
= 854
Hence, number of girls in school this year in 854.
- In a particular constituency, 75% of voters cast their votes, out of which 2% were rejected. The winning candidate received 75% of the valid votes and bagged a total of 9261 votes. The total number of voters in the constituency is
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Let the total number of votes = N
According to the question,
75% of 98% of 75% of N = 9261
[∵ 2% votes were rejected]
⇒ (N x 75 x 98 x 75) / (100 x 100 x 100) = 9261Correct Option: C
Let the total number of votes = N
According to the question,
75% of 98% of 75% of N = 9261
[∵ 2% votes were rejected]
⇒ (N x 75 x 98 x 75) / (100 x 100 x 100) = 9261
∴ N = (9261 x 100 x 100 x 100) / (75 x 75 x 98) = 16800
- from 2008 to 2009, the sales of a book decreased by 80%. If the sales in 2010 was the same as in 2008, by what per cent did it increase from 2009 to 2010 ?
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Let sale in 2008 = 100
Sale in 2009 = 20
Sale in 2010 = 100
∴ Required increases = [(100 - 20)/20] x100Correct Option: D
Let sale in 2008 = 100
Sale in 2009 = 20
Sale in 2010 = 100
∴ Required increases = [(100 - 20)/20] x100
= (80/20) x 100 = 400%
- The price of two article are as 3 : 4. If the price of the first article is increased by 10% and that if the second by ₹ 4 one original ratio remains the same. The original price of the second article is
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Let cost prices of two article be 3N and 4N respectively then
(110% of 3N) / (4N + 4) = 3/4
⇒ 1.1N / (N + 1) = 1Correct Option: A
Let cost prices of two article be 3N and 4N respectively then
(110% of 3N) / (4N + 4) = 3/4
⇒ 1.1N / (N + 1) = 1
⇒ 1.1N = N + 1
⇒ 0.1 N = 1
⇒ N = 10
Thus, cost price of the second article is 4 x 10 = ₹ 40
