Percentage
- If A's salary is 30% more than B's then how much per cent is B's salary less than A's ?
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B's salary is less than A's by (30 x 100)/130 % = 231/13%
Correct Option: C
B's salary is less than A's by (30 x 100)/130 % = 231/13%
- P is six times as large as q. The per cent that q is less than p,is ?
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P = 6q. Thus q is less than p by 5q
∴ q is less than p by = {(6q - q)/6q} x 100%Correct Option: A
P = 6q. Thus q is less than p by 5q
∴ q is less than p by = {(6q - q)/6q} x 100%
= ( 5q/6q) x 100 % = 831/3 %
- A man's wages were decreased by 50%. Again the reduced wages were increased by 50%. He has a loss of ?
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Let original wages = Rs. 100
Reduced wages = Rs. 50
Increased wages = 150% of Rs. 50 = (150 x 50)/100 = Rs. 75Correct Option: D
Let original wages = Rs. 100
Reduced wages = Rs. 50
Increased wages = 150% of Rs. 50 = (150 x 50)/100 = Rs. 75
∴ Loss = 25%
- The population of a town increase 4% annually but is decreases by emigration annually to the extent of 1/2%. What will be the increase percent in three years ?
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Increase in 3 years over 100 = 100 x {1 + 7/(2 x 100)}3
= (100 x 207/200 x 207/200 x 207/200)
= (200 + 7)3 / 80000
= 88869743 / 80000 = 110.8718Correct Option: D
Increase in 3 years over 100 = 100 x {1 + 7/(2 x 100)}3
= (100 x 207/200 x 207/200 x 207/200)
= (200 + 7)3 / 80000
= 88869743 / 80000 = 110.8718
Required increase % = (110.8 - 100)% = 10.8%
- The value of a machine depreciates 10% annually. If its present value is Rs. 4000. Its value 2 years later will be ?
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Value of machine 2 years later = Rs. [ 4000 x {(1 - 10)/10)}2]
= Rs. (4000 x 9/10 x 9/10)Correct Option: B
Value of machine 2 years later = Rs. [ 4000 x {(1 - 10)/10)}2]
= Rs. (4000 x 9/10 x 9/10)
= Rs. 3240