Marks secured by Anirudh = [(85/100) x 100] + [(70/100) x 120] + [(65/100) x 140] + [(60/100) x 160]
= (85 + 84 + 91 + 96) = 356

Correct Option: B

Marks secured by Anirudh = [(85/100) x 100] + [(70/100) x 120] + [(65/100) x 140] + [(60/100) x 160]
= (85 + 84 + 91 + 96) = 356
∴ Required percentage = [356/(100 + 120 + 140 + 160)] x 100 %
= (356/520) x 100% = 68⁶/₁₃%

Let the number be N.
Then, error = 5N/2 - 2N/5 = 21N/10
∴ Error percentage = (21N/10) x (2/5N) x 100 %

Correct Option: C

Let the number be N.
Then, error = 5N/2 - 2N/5 = 21N/10
∴ Error percentage = (21N/10) x (2/5N) x 100 % = 84%

Let the original price be ₹ N per kg.
New price per kg = 60% of N = 3N/5
∴ 120 / (3N/5) - 120/N = 32

Correct Option: B

Let the original price be ₹ N per kg.
New price per kg = 60% of N = 3N/5
∴ 120 / (3N/5) - 120/N = 32
⇒ 600/3N - 120/N = 32
⇒ 200/N - 120/N = 32
⇒ 80/N = 32
∴ N = 80/32 = 2.5
So, the original price is ₹ 2.50

Sum of CP pf table and chair = Sum of SP of table and Chair

Correct Option: B

CP of the chair which is sold at 25% of profit = Rs 4000/ (1+ 25%)
= Rs 4000/1.25
= Rs 3200

Now given, that sum of CP pf table and chair= sum of SP of table and Chair
⇒ 8000= 3200 + CP of Table
⇒ CP of Table = Rs 4800
⇒ Loss on Cost price of table = Rs 4800- Rs 4000= Rs 8000
⇒ Loss % = 8000/4800 = 16.66%

∵ 5% of A=15% of B and 10% of B = 20% of C
∴ A/20 = 3B/20 and B/10 = C/5
⇒ B = 2C
⇒ A/20 = (3/20) x 2C = 3C/10 =(3/10) x 2000 = 600
∴ A = (600 x 20) = 12000,
B = (2 x 2000) = 4000

Correct Option: B

∵ 5% of A=15% of B and 10% of B = 20% of C
∴ A/20 = 3B/20 and B/10 = C/5
⇒ B = 2C
⇒ A/20 = (3/20) x 2C = 3C/10 =(3/10) x 2000 = 600
∴ A = (600 x 20) = 12000,
B = (2 x 2000) = 4000
∴ A + B + C = (12000 + 4000 + 2000) = 18000