Percentage
- The population of a town is 705600. If it increases at the rate of 5% per annum, then what will be its population 2yr hence ?
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Given that,
P = 705600, R = 5% and n = 2
According to the formula,
Population after n yr = p(1 + R/100)nCorrect Option: A
Given that,
P = 705600, R = 5% and n = 2
According to the formula,
Population after n yr = p(1 + R/100)n
∴ Population after 2 yr.
= 705600 x (1+ 5/100)2
= 705600 x (105/100)2
= 705600 x (21/20 x 21/20) = 777924
- The population of a town is 126800. It increase by 15% in the 1st year and decrease by 20% in the 2nd year. What is the population of the town at the end of 2 yr.
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Given, R = 15% and R2 = 20%
Required population
= P(1 + R1/100) (1 - R2/100)Correct Option: C
Given, R = 15% and R2 = 20%
Required population
= P(1 + R1/100) (1 - R2/100)
= 126800(1 + 15/100) (1- 20/100)
= 126800 (1 + 3/20 ) (1- 1/5)
= 126800 x (23/20) x (4/5) = 116656
- A man losses 20% of his money. After sending 25 % of the remainder, he has ₹ 480 left. What is the amount of money he originally had ?
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Let a man have = ₹ N.
Remainder money, after losses 20% of his money
= N - 20% of N
Remainder money, after spending 25% of his remainder money
= 4N/5 - 25% of (4N/5)Correct Option: C
Let a man have = ₹ N.
Remainder money, after losses 20% of his money
= N - 20% of N
= N - (N x 20)/100
= (5N - N)/5
= 4N/5
Remainder money, after spending 25% of his remainder money
= 4N/5 - 25% of (4N/5)
= 4N/5 - (4N/5) x (25/100)
= 4N/5 - N/5
= (4N - N)/5
= 3N/5
According to the question,
3N/5 = 480
⇒ x = 480 x 5/3 = ₹ 800
- In an examination, the marks obtained by Shantanu is 40% less than the marks obtained by Kamal, then marks obtained by Kamal is how much per cent more than the marks obtained by Shantanu ?
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Let kamal's marks be 100
∴ Shantanu's marks = 60
Kamal has 40 marks more than Shantanu
∴ Required percentage = (40/60) x 100%Correct Option: D
Let kamal's marks be 100
∴ Shantanu's marks = 60
Kamal has 40 marks more than Shantanu
∴ Required percentage = (40/60) x 100%
= 662/3 %
- 12 of 26% of 5/78 of 38% of 7/152 of 10000 = ?
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Ans = 12 x (26/100) x (5/78) x (38/100) x (7/152) x 10000
Correct Option: B
Ans = 12 x (26/100) x (5/78) x (38/100) x (7/152) x 10000
= 12 x (5/3) x (7/4)
= 35