Percentage


  1. The population of a town is 705600. If it increases at the rate of 5% per annum, then what will be its population 2yr hence ?











  1. View Hint View Answer Discuss in Forum

    Given that,
    P = 705600, R = 5% and n = 2

    According to the formula,
    Population after n yr = p(1 + R/100)n

    Correct Option: A

    Given that,
    P = 705600, R = 5% and n = 2

    According to the formula,
    Population after n yr = p(1 + R/100)n

    ∴ Population after 2 yr.
    = 705600 x (1+ 5/100)2
    = 705600 x (105/100)2
    = 705600 x (21/20 x 21/20) = 777924


  1. The population of a town is 126800. It increase by 15% in the 1st year and decrease by 20% in the 2nd year. What is the population of the town at the end of 2 yr.











  1. View Hint View Answer Discuss in Forum

    Given, R = 15% and R2 = 20%
    Required population
    = P(1 + R1/100) (1 - R2/100)

    Correct Option: C

    Given, R = 15% and R2 = 20%
    Required population
    = P(1 + R1/100) (1 - R2/100)
    = 126800(1 + 15/100) (1- 20/100)
    = 126800 (1 + 3/20 ) (1- 1/5)
    = 126800 x (23/20) x (4/5) = 116656



  1. A man losses 20% of his money. After sending 25 % of the remainder, he has ₹ 480 left. What is the amount of money he originally had ?









  1. View Hint View Answer Discuss in Forum

    Let a man have = ₹ N.
    Remainder money, after losses 20% of his money
    = N - 20% of N

    Remainder money, after spending 25% of his remainder money
    = 4N/5 - 25% of (4N/5)

    Correct Option: C

    Let a man have = ₹ N.
    Remainder money, after losses 20% of his money
    = N - 20% of N
    = N - (N x 20)/100
    = (5N - N)/5
    = 4N/5

    Remainder money, after spending 25% of his remainder money
    = 4N/5 - 25% of (4N/5)
    = 4N/5 - (4N/5) x (25/100)
    = 4N/5 - N/5
    = (4N - N)/5
    = 3N/5

    According to the question,
    3N/5 = 480
    ⇒ x = 480 x 5/3 = ₹ 800


  1. In an examination, the marks obtained by Shantanu is 40% less than the marks obtained by Kamal, then marks obtained by Kamal is how much per cent more than the marks obtained by Shantanu ?











  1. View Hint View Answer Discuss in Forum

    Let kamal's marks be 100
    ∴ Shantanu's marks = 60
    Kamal has 40 marks more than Shantanu
    ∴ Required percentage = (40/60) x 100%

    Correct Option: D

    Let kamal's marks be 100
    ∴ Shantanu's marks = 60
    Kamal has 40 marks more than Shantanu
    ∴ Required percentage = (40/60) x 100%
    = 662/3 %



  1. 12 of 26% of 5/78 of 38% of 7/152 of 10000 = ?











  1. View Hint View Answer Discuss in Forum

    Ans = 12 x (26/100) x (5/78) x (38/100) x (7/152) x 10000

    Correct Option: B

    Ans = 12 x (26/100) x (5/78) x (38/100) x (7/152) x 10000
    = 12 x (5/3) x (7/4)
    = 35