Percentage
- The length and breadth of square are increased by 30% and 20% respectively. The area of the rectangle so formed exceeds the area of the square by ?
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Let length of square = 100 m and breadth of square = 100 m
Area = (100 x 100) m2 = 10000 m2
New length = 130 m and breadth = 120 mCorrect Option: D
Let length of square = 100 m and breadth of square = 100 m
Area = (100 x 100) m2 = 10000 m2
New length = 130 m and breadth = 120 m
New area of rectangle = (130 x 120) m2 = 15600 m2
Increase % = (5600 / 10000) x 100 % = 56%
- The radius of circle is increased by 1%. What is the increased percent in its area ?
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Let radius of circle = 100 m
New radius = 101 m
original area = [π x (100)2 ]m2
New area = [π x (101)2 ]m2Correct Option: D
Let radius of circle = 100 m
New radius = 101 m
original area = [π x (100)2 ]m2
New area = [π x (101)2 ]m2
Increase% = [π x {(101)2 - (100)2} / { π x (100)2} ] x 100 %
= 201 / 100% = 2.01%
- If the side of a square is increased by 30%, its area is increased by ?
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View Hint View Answer Discuss in Forum
Let side of square = 100 cm
Area = (100 x 100)cm2 = 10000 cm2
New area = (130 x 130)cm2 = 16900 cm2Correct Option: D
Let side of square = 100 cm
Area = (100 x 100)cm2 = 10000 cm2
New area = (130 x 130)cm2 = 16900 cm2
Increase in area = (6900 / 10000) x 100% = 69%
- 72% of the students of a certain class took Biology and 44% took Mathematics. If each student took Biology or Mathematics and 40 took both. The total number of students in the class was ?
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Let the total number of students be 100
Then, n(A ∩ B) = n(A) + n(B) - n(A ∪ B) = (72 + 44 - 100)% = 16%
Now,16% of N = 40Correct Option: C
Let the total number of students be 100
Then, n(A ∩ B) = n(A) + n(B) - n(A ∪ B) = (72 + 44 - 100)% = 16%
Now,16% of N = 40
⇒ (16 x N) / 100 = 40
∴ N = (100 x 40) / 16 = 250